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artcher [175]
2 years ago
14

I need help ASAP please ant thank you what is x

Mathematics
1 answer:
Marizza181 [45]2 years ago
6 0

Answer:

(3x-17)°+(x+40)°+(2x-5)°=180°[sum of angle of triangle]

6x°+18°=180°

6x°=180°-18°

x°=162°÷6°

x°=27°

Again,

=3x-17. 2x-5. x+40°

=3×27-17. =2×27-5. =27+40

=64°. =49°. =67°

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For this case we have the following equation:
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7 0
3 years ago
IM GIVING BRAINLIEST!! suppose F is a 10-newton vector direction 60 degrees north of east and g is a 12-newton vector directed 4
Sonbull [250]

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8 0
2 years ago
Among the four northwestern states, Washington has 51% of the total population, Oregon has 30%, Idaho has 11%, and Montana has 8
morpeh [17]

Answer:

Step-by-step explanation:

H₀ : The distribution of the sample agrees with the population distribution.

H₁ : the distribution of the does not agree with the population distribution.

Using the  Chi-square test statistics

we will compute the expected frequencies

Now expected frequency for Washington will be

Fe = Npi = 1000×51% = 5100

expected frequency for Oregon

Fe = Npi = 1000×30% = 300

expected frequency for Idaho

Fe = Npi = 1000×11% = 110

expected frequency for  Montana

Fe = Npi = 1000×8% = 80

The Chi=square test statistics is;

x² = ∑ [ (Fo - Fe)² / Fe )

now we substitute

Given our Fo ( 450 in Washington, 340 in Oregon, 150 in Idaho, and 60 in Montana) from the question

x² =  (450-510)²/510 + (340-300)²/300 + (150-110)²/110 + (60-80)²/80

x²= 31.9376

so the chi-square test statistics is 31.9376

Now the chi-square critical value

first we compute for degree of freedom

d.f = k -1 = 4 - 1 = 3

So from the critical value table, degree of freedom 3 and significance level 0.05,

the chi-square critical value is 7.8147

Therefore chi-square test statistics 31.9376 is greater than the chi-square critical value 7.8147, so NULL HYPOTHESIS IS REJECTED at 5% significance.

There is sufficient evidence to warrant rejection  of the claim that the distribution of the sample agrees with the distribution of the state populations.

3 0
3 years ago
Let v1=(1, 6) and v2=(5, -3)
astraxan [27]

Answer:

See Explanation;

Step-by-step explanation:

The given vectors are;

v_1=\:\: and v_2=\:\:

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v_1+v_2=\:\:+\:\:

v_1+v_2=\:\:

v_1+v_2=\:\:

v_1-v_2=\:\:-\:\:

v_1-v_2=\:\:

v_1-v_2=\:\:

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b) See attachment for graphs(1,6

3 0
2 years ago
Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

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Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
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