Someone plz help me with this

Erica must tutor a minimum of 20 hours per week in order to remain in the national honor society. She has a student that she tut

irinina [24]

Answer:

3 hours every weekday

Step-by-step explanation:

20 - 5 is 15 so she must work 15 hours during the week since saturday and sunday are taken. 15 divided by 5 is 3 therefore, giving you three hours a day; Monday, Tuesday, Wednesday, Thursday, and Friday

8 0

3 years ago

At a grocery store, the price of a watermelon is determined by how many pounds the watermelon weighs. The price of a watermelon

Alexxx [7]

Answer:

$p=0.60w$

Step-by-step explanation:

Let

p ----> the price of a watermelon in dollars

w ---> the weight of a watermelon in pounds

In this problem we have a proportional relationship

Remember that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem

$p=kw$

The value of the constant of proportionality k is the same that the unit rate

Find out the unit rate

Divide the total cost by the total weight

$k=\frac{4.38}{7.3}=\$0.60\ per\ pound$

substitute in the equation

$p=0.60w$

7 0

3 years ago

The width of a rectangle is 3 feet less than it’s length. The perimeter of the rectangle is 98 feet. Find the dimensions of the

horsena [70]

Answer:

The length is 26 feet and the width is 23 feet

Step-by-step explanation:

Let l represent the length of the rectangle.

The width can be represented by l - 3, since it is 3 feet less than the length

Set up an equation:

l + l + (l - 3) + (l - 3) = 98

Add like terms and solve for l:

l + l + (l - 3) + (l - 3) = 98

4l - 6 = 98

4l = 104

l = 26

So, the length is 26 feet.

Since the width is l - 3, we can plug this in for l to find the width:

l - 3

26 - 3

= 23

So, the length is 26 feet and the width is 23 feet

4 0

3 years ago

Please help.<br> Is algebra.

Airida [17]

Answer:

i believe

the first one it's (0,3)

the second is (4, -7)

3 0

3 years ago

83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi

arlik [135]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

Step-by-step explanation:

Information given

$\bar X=32.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom given by:

$df=n-1=8-1=7$

The confidence level is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

$\chi^2_{\alpha/2}=104.139$

$\chi^2_{1- \alpha/2}=62.132$

The confidence interval is given by:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.525 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.127 \leq \sigma \leq 2.757$

5 0

3 years ago