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jasenka [17]
3 years ago
13

Someone plz help me with this

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

this is the answer. it moved down 5 from 0

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Simplify each expression as much as possible, and rationalize denominators when applicable. √72=?
Misha Larkins [42]

Answer:

6√2

Step-by-step explanation:

Solving the given expression step by step:

72 = 2 × 2 × 2 × 3 × 3

Now for finding the square root we will make pair of two numbers of same values.

We have one pair of 2's and one pair of 3's and left one 2

Thus, √72 = 2 × 3 × √2 = 6√2

We rationalize denominator and change it into a simpler form as soon as possible.

3 0
3 years ago
What is a 3 dimensional figure with 3 rectangular faces and 2 triangular faces
Margaret [11]
     The Answer is Triangular Prism.                       
8 0
3 years ago
The table shows some ordered pairs that belong to the quadratic function h.
erastova [34]

Answer:

C. Are all real numbers greater than or equal to -8.

Step-by-step explanation:

Real numbers can be said to be all continuous values of quantity, which can be negative or positive values.

The range of h, h(x), in the table given are all real numbers.

The least of the range of h on the table is -8. All the other range values, namely, -7, 1, 17, and 41 are all greater than -8. None is less than -8.

Therefore, we can conclude that the range values of h "are all real numbers greater than or equal to -8".

6 0
3 years ago
How to solve with exponents and negatives
Oliga [24]
multiply by negative 1
8 0
3 years ago
Read 2 more answers
Find the equation for the line passing through the point (−1,1) ( − 1 , 1 ) and parallel to the line whose equation is y=2x+12.
tekilochka [14]
So, parallel lines have the same slope, therefore a parallel line to 2x+12, will have the same slope as that one, so which is it?   \bf y=\stackrel{slope}{2}x\stackrel{y-intercept}{+12}

so, we're really looking for the equation of a line whose slope is 2, and runs through -1,1.

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ -1}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 2
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-1=2[x-(-1)]
\\\\\\
y-1=2(x+1)\implies y-1=2x+2\implies y=2x+3
7 0
3 years ago
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