3. f(-6) = 12+1 =13
f(-2) = 4+1 = 5
f(0) =1
Range {1,5,13}
4. f(-2) = (-2)^3+1 =-7
f(-1) = (-1)^2 +1 =0
f(3) = (3)^3 +1 = 28
Range = {-7,0,28}
5.the sequence is arithmetic
d= -11+19 = 8
an = a1 + d(n-1)
an = -19 +8(n-1)
6.l =w+5
a =l*w
a(w) =(w+5) * w
a(w)= w^2 +5w
f(w) = w^2 +5w
f(8) = 8^2 +5(8)
f(8) = 64 +40
f(8) =104 in^2
Answer: y≤0
Step-by-step explanation:
Looking at the question, I'm assuming the equation is
.
To find the range if this equation, it would be best to know that the graph of a square root looks like. Knowing that x=-5, the graph starts at -5 and then increases slowly to the right. Since there are no restrictions to this equation, the graph goes towards infinity.
∣2x+7∣ for x=-4
Use the substitution method
∣2*-4+7∣
Mutiply first then add +7
∣2*-4∣= -8
∣-8+7∣= -1
Whenever there is a negative number for absolute value , the number becomes a + positive number.
∣-1∣= 1
Answer:
1
Answer:
Those points are
units apart.
Answer: a. 90°
Step-by-step explanation:
We know that the in a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.
In the problem∠XYZ is the inscribed angle
∠XYZ=
⇒ ∠XYZ=
Since XZ is a diameter of the circle which is a line segment, thus ∠XZ=180°
∴ ∠XYZ=
∴ ∠XYZ=
Therefore, a. 90° is the measure of ∠XYZ.