A5= -68 and r=-0.5 ; find a1

Veronica was recently diagnosed with a heart condition. Her doctor's bill was $4,200 for the diagnostics. Her policy has a $250

Nadusha1986 [10]

Answer:

$1040

Step-by-step explanation:

As 80/20 insurance policy is a form of coinsurance in which deductible is satisfied first and then the client would pay 20% of additional medical costs and the remaining 80% is paid by the insurance company. Under the current scenario, Veronica will bear an amount of $250 and $790(i.e. 20% of the amount after deductible), totaling to $1040.

4 0

3 years ago

A study analyzed the average yearly salt intake in the United States from 2012 thru 2017. The data is summarized in the table: Y

Nuetrik [128]

Answer:

Is an estimate of the average grams of salt used in 2012

Step-by-step explanation:

Let

x ---> the number of years since 2012

f(x) ---> is the total amount of salt ingested in grams

we have

$f(x)=52.3x+3.548$

This is a linear equation in slope intercept form

where

The slope is equal to

$m=52.3\ grams/ year$

The y-intercept or initial value is equal to

$b=3,548\ grams$

The y-intercept is the value of the function f(x) when the value of x is equal to zero

In this context, the y-intercept is the average amount of grams of salt ingested in the year 2012

The exact value of the average amount of grams of salt ingested in the year 2012 is 3,554 grams (see the data in the table)

Compare the exact value with the y-intercept

$3,554\ g\neq 3,548\ g$

therefore

3,548 grams Is an estimate of the average grams of salt used in 2012

7 0

3 years ago

De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de

Sunny_sXe [5.5K]

Answer:

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

$M \propto \frac{r^{3}}{T^{2}}$

$M = k\cdot \frac{r^{3}}{T^{2}}$ (Eq. 1)

Donde:

$r$ - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

$T$ - Período oribital del satélite, medido en días.

$k$ - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

$M$ - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

$\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }$

$\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}$ (Eq. 2)

Donde:

$T_{M}$ , $T_{E}$ - Períodos orbitales de la Luna y la Tierra, medidos en días.

$r_{E}$ , $r_{M}$ - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

$M_{S}$ , $M_{E}$ - Masas del Sol y la Tierra, medidos en kilogramos.

Si $M_{E} = 75.97\times 10^{24}\,kg$ , $T_{E} = 365.3\,d$ , $T_{M} = 27.3\,d$ , $r_{M} = 3.84\times 10^{5}\,km$ y $r_{E} = 1.496\times 10^{8}\,km$ , entonces tenemos que la masa del Sol es:

$M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}$

$M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)$