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Misha Larkins [42]
2 years ago
7

Help me asap!!! Can’t figure it out for a test

Mathematics
1 answer:
o-na [289]2 years ago
8 0

Answer:

C. (0, -1) maximum

Step-by-step explanation:

look at the graph. notice that the graph only goes as high as the very top of the parabola, and then the rest of it just gets lower in number.

since it only gets as high in value as the top point, thats called a maximum.

that top point's coordinates are (0, -1)

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Solve the equation for x.
Airida [17]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
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A rectangular window measures 54 inches by 24 inches. There is an a = 14-inch wiper blade attached by a b = 5-inch arm at the ce
nika2105 [10]
It the wiper blade (and arm) made a full rotation, 2 circles would be formed.

One small circle with radius b, and a larger circle with radius a+b.


The areas of these 2 circles are respectively:

\pi b^2=\pi\cdot 5^2=25 \pi (in^2)    and

\pi (a+b)^2=\pi (14+5)^2=361\pi (in^2)


120° is 1/3 of a complete angle 360° which form a circle, so the areas formed by the arm of length b, and the arm + the wiper blade (a+b) are:

\frac{25 \pi}{3} and \frac{361\pi}{3} in squared respectively.

the actual wiped area is \frac{361\pi}{3}-\frac{25 \pi}{3}= \frac{336\pi}{3}=112\pi \approx351.7 (in squared)


Area of the window is 54*24= 1296 (in squared)

thus, the ratio of the wiped area to the whole area of the window is 351.7/1296=0.271

Converted to percentages, this is 27.1%


Answer: 27.1%

3 0
3 years ago
1000*0+321*15678*9(-4563)
Vikki [24]

Answer:

-206675344746

Step-by-step explanation:

1000*0+321*15678*9(-4563) = -206675344746

7 0
2 years ago
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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

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2 years ago
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Alexandra [31]

Answer:

That looks hard

Step-by-step explanation:

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