Suppose you have developed a scale that indicates the brightness of sunlight. Each

1 answer:

3 0

The comparison of brightness between a dazzling day than a dim day is that; a dazzling day is; 512 times brighter.

<h3>How many times brighter is a dazzling day than a dim day?</h3>

It follows from the task content that each category in the table is 8 times brighter than the next lower category.

Hence, since a dazzling day has a degree of brightness of 5 while a dim day has a degree of 2, leaving the difference to be; 5-2 = 3.

Hence, the dazzling is therefore; 8³ times brighter than the dim day = 512 times brighter.

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Minchanka [31]

5.8 0.8 5.9 6.1 and 10.9 are all correct answers.

Hope this Helped!

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4 0

3 years ago

Y_Kistochka [10]

$\bold{\huge{\underline{ Solution }}}$

Before answering the given question, you should know the difference between polygon and regular polygon. 

Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles.
Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .

There are different types of polygon based on the sides :-

A polygon having 3 sided called triangle ,having 4 sides called quadrilateral ,having 5 sides pentagon and so on.

<h3>Let's Begin :-</h3>

I have thought to make a 4 side polygon that is quadrilateral.

Steps of construction :-

Step - 1 :- Draw a 5 cm line AB horizontally
Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC
Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD
Step - 4 :- Now, join the line AD
Step - 5 :- Measure all the angles form by the 4 sides of the quadrilateral.