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tresset_1 [31]
2 years ago
13

Suppose you have developed a scale that indicates the brightness of sunlight. Each

Mathematics
1 answer:
Contact [7]2 years ago
3 0

The comparison of brightness between a dazzling day than a dim day is that; a dazzling day is; 512 times brighter.

<h3>How many times brighter is a dazzling day than a dim day?</h3>

It follows from the task content that each category in the table is 8 times brighter than the next lower category.

Hence, since a dazzling day has a degree of brightness of 5 while a dim day has a degree of 2, leaving the difference to be; 5-2 = 3.

Hence, the dazzling is therefore; 8³ times brighter than the dim day = 512 times brighter.

Read more on exponential relationship;

brainly.com/question/2456547

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What is 0.0000091 written in scientific notation
zaharov [31]
The goal of writing a number in scientific notation is to have a decimal number, with one digit to the left of the decimal point, followed by a <span>×⨯</span><span>1010</span> to some power. To format the number this way, multiply the <span>0.00000910.0000091</span> by <span>1010</span> <span><span>−6</span><span>-6</span></span> times, making it <span>9.19.1</span>. Each multiplication by <span>1010</span> moves the decimal point one digit to the left, but in order to keep the same number, multiply <span>9.19.1</span> by <span><span>10<span>−6</span></span><span>10<span>-6</span></span></span>.<span>9.1×<span>10<span>−<span>6</span></span></span></span>
8 0
3 years ago
Read 2 more answers
Do number 4 please DONT get it wrong or i block report, i really need help please :)
andriy [413]

Area of the figure = 30.28 m²

Solution:

The given image is splitted into two shapes.

One is rectangle and the other is semi-circle.

Length of the rectangle = 6 m

Width of the rectangle = 4 m

Area of the rectangle = length × width

                                    = 6 m × 4 m

                                    = 24 m²

Area of the rectangle = 24 m²

Diameter of the semi-circle = 4 m

Radius of the semi-circle = 4 m ÷ 2 = 2 m

Area of the semi-circle = \frac{1}{2} \ \pi r^2

                                      $=\frac{1}{2} \times 3 .14 \times 2^2

                                      =6.28

Area of the semi-circle = 6.28 m²

Area of the figure = Area of the rectangle + Area of the semi-circle

                              = 24 m² + 6.28 m²

                              = 30.28 m²

Area of the figure = 30.28 m²

3 0
3 years ago
Joe is placing tile in a small rectangular room. The room measures 8 feet by 5.5 feet. If one square foot tiles are sold in pack
Anit [1.1K]

Answer:

4

Step-by-step explanation:

The area, a of the room is 8* 5.5

a = 44 sqaure feet

one square foot of tiles are sold in packages of 12

To get the number of packages needed, simply divide the area of the room by 12

This gives:

44/12 = 4

= 3.67   round up to the nearest whole number

= 4

6 0
3 years ago
The number of yards of fabric needed for Robs costume is (7/8+1/2+1 3/4)÷2. How does the amount of fabric needed for Robs costum
exis [7]

The amount of fabric needed for Jimmy's costume is not stated, we can only determine the amount needed for Rob's costume, which makes it impossible to compare the amounts needed for both of their costumes. If this omission was an error, then you can find the difference between these amounts if the amount needed for Jimmy's costume is stated explicitly.

Step-by-step explanation:

The number of yards of fabric needed for Robs costume is (7/8+1/2+1 3/4)÷2

Assuming 1 3/4 is a mixed fraction.

= (7/8 + 1/2 + 7/4) ÷ 2

= (7 + 4 + 2) ÷ (8 × 2)

= 13/16 yards

Suppose 2 yards of fabric is needed for Jimmy's costume, then comparing with Rob's yards, we see that Jimmy's costume requires (2 - 13/16 = 19/16) more yards than Rob's costume.

8 0
3 years ago
I need help on 12 please :)
alisha [4.7K]

Answer:

the answer is 10 to the 5th power

Step-by-step explanation:


6 0
3 years ago
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