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tresset_1 [31]
2 years ago
13

Suppose you have developed a scale that indicates the brightness of sunlight. Each

Mathematics
1 answer:
Contact [7]2 years ago
3 0

The comparison of brightness between a dazzling day than a dim day is that; a dazzling day is; 512 times brighter.

<h3>How many times brighter is a dazzling day than a dim day?</h3>

It follows from the task content that each category in the table is 8 times brighter than the next lower category.

Hence, since a dazzling day has a degree of brightness of 5 while a dim day has a degree of 2, leaving the difference to be; 5-2 = 3.

Hence, the dazzling is therefore; 8³ times brighter than the dim day = 512 times brighter.

Read more on exponential relationship;

brainly.com/question/2456547

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Josie found a job with an annual salary of $67.3K. What is her monthly pay, rounded to the nearest dollar?
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Answer:

$5,608

Step-by-step explanation:

Since there are 12 months in one year, divide her annual salary by 12.

$67,300/12 = $5,608.33 ≈ $5,608

Josie makes $5,608 per month.

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there are 30 students in mr. Holland music class. If 30% of the students play in the school band, how many students in the class
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3 years ago
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Plsss help no one answered the other times I put this question
svetlana [45]

Answer:

a) <em>The equation</em> (10s + 8w) <em>represents </em><em>the </em><em>calories </em><em>Bridget </em><em>ate </em><em>on </em><em>Monday </em><em>and </em><em>the </em><em>equation</em> (20s + w) <em>represents </em><em>the </em><em>calories</em><em> </em><em>she </em><em>ate</em><em> </em><em>the </em><em>next </em><em>day.</em>

<em>b)</em><em> </em><em>The </em><em>number </em><em>of </em><em>calories</em><em> </em><em>in </em><em>each </em><em>strawberry</em><em> </em><em>is </em>4 <em>and </em><em>the </em><em>number </em><em>of </em><em>calories </em><em>in </em><em>each </em><em>vanilla</em><em> </em><em>wafer</em><em> cookie</em><em> </em><em>is </em>19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is <em>s</em> and the number of calories in a vanilla wafer cookie is <em>w </em>, the number of calories Bridget ate on Monday is <em>10s + 8w</em><em>.</em><em> </em>The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s<em> + w</em>.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

7 0
3 years ago
Consider the linear and quadratic functions appearing in the figure below.
Bumek [7]

Answer:

step 2:do subtraction in the parentheses  

Step 3: distribute

Step 4: add

Step-by-step explanation:

4 0
3 years ago
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