The answer to your question would be 150 (c)
In this equation w = -1.1
In order to find this, get all w values to the right side and all numbers to the left side.
-2.27 + 9.1w + 1.3w = -3.4w - 17.45 ----> combine like terms
-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides
-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides
13.8w = -15.18 -----> divide both sides by 13.8
w = -1.1
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10
Answer:
The answer is 6.3
Step-by-step explanation:
Answer:
8sin(x)cos³(x)
Step-by-step explanation:
sin(4x) +2 sin(2x) = 2sin(2x)*cos(2x) + 2sin(2x) = 2sin(2x)(cos2x + 1)=
= 2sin(2x)(cos²x - sin²x + cos²x + sin²x)=²2sin(2x)*(2cos²x)=
= 4*2sin(x)*cos(x)*cos²(x)= 8sin(x)cos³(x)
