The diameter of a circle is 18m . Find its circumference in terms of pi?
2 answers:
<h2><u>Question</u>:-</h2>
The diameter of a circle is 18 m. Find its circumference in terms of π.
<h2><u>Solution</u>:-</h2>Diameter of a circle = 18 m. (Given)
Radius (r) of a circle = 18/2 = 9 m.
We know,
Circumference of a circle is 2πr.
So, It's circumference is (2 × π × 9) m.
It's circumference is 18π m.
<h3>It's circumference in terms of π is <u>1</u><u>8</u><u>π</u><u> </u><u>m</u>. [Answer]</h3>You might be interested in
Given:
Equilateral Triangular Prism
Each side of the triangular face has a length of 196cm
The tent is 250cm long
I have attached an image of the tent. Since the height of the tent is also the height of the triangle, I will solve for the height of the triangle using Pythagorean theorem.
I divided the equilateral triangle into 2 right triangle. The height then becomes the long leg of the triangle. The hypotenuse is 196cm and the short leg is 98cm, half of one side of the triangle.
a² + b² = c²
a² = c² - b²
a² = (196cm)² - (98cm)²
a² = 38,416cm² - 9,604cm²
a² = 28,812cm²
a = √28,812cm²
a = 169.74cm
The height of the tent is 169.74 centimeters.
Equilateral Triangular Prism
Each side of the triangular face has a length of 196cm
The tent is 250cm long
I have attached an image of the tent. Since the height of the tent is also the height of the triangle, I will solve for the height of the triangle using Pythagorean theorem.
I divided the equilateral triangle into 2 right triangle. The height then becomes the long leg of the triangle. The hypotenuse is 196cm and the short leg is 98cm, half of one side of the triangle.
a² + b² = c²
a² = c² - b²
a² = (196cm)² - (98cm)²
a² = 38,416cm² - 9,604cm²
a² = 28,812cm²
a = √28,812cm²
a = 169.74cm
The height of the tent is 169.74 centimeters.