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Nuetrik [128]
3 years ago
13

The diameter of a circle is 18m . Find its circumference in terms of pi?

Mathematics
2 answers:
liraira [26]3 years ago
6 0
<h2><u>Question</u>:-</h2>

The diameter of a circle is 18 m. Find its circumference in terms of π.

<h2><u>Solution</u>:-</h2>

Diameter of a circle = 18 m. (Given)

Radius (r) of a circle = 18/2 = 9 m.

We know,

\dag Circumference of a circle is 2πr.

So, It's circumference is (2 × π × 9) m.

It's circumference is 18π m.

<h3>It's circumference in terms of π is <u>1</u><u>8</u><u>π</u><u> </u><u>m</u>. [Answer]</h3>
never [62]3 years ago
5 0

Answer:

The circumference of a circle =πd = π×18 =18π m

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URGENT HELP ME PLEASE
Trava [24]

Answer:

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(b)\log_5(\dfrac{625}{25})=2

(c)\log_2(\dfrac{64}{8})=3

(d)\log_4(\dfrac{64}{16})=1

(e)\log_6(36^4)=8

(f)\log(100^3)=6

Step-by-step explanation:

Let as consider the given equations are \log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?.

(a)

\log_3(\dfrac{81}{3})=\log_3(27)

\log_3(\dfrac{81}{3})=\log_3(3^3)

\log_3(\dfrac{81}{3})=3        [\because \log_aa^x=x]

(b)

\log_5(\dfrac{625}{25})=\log_5(25)

\log_5(\dfrac{625}{25})=\log_5(5^2)

\log_5(\dfrac{625}{25})=2        [\because \log_aa^x=x]

(c)

\log_2(\dfrac{64}{8})=\log_2(8)

\log_2(\dfrac{64}{8})=\log_2(2^3)

\log_2(\dfrac{64}{8})=3        [\because \log_aa^x=x]

(d)

\log_4(\dfrac{64}{16})=\log_4(4)

\log_4(\dfrac{64}{16})=1        [\because \log_aa^x=x]

(e)

\log_6(36^4)=\log_6((6^2)^4)

\log_6(36^4)=\log_6(6^8)

\log_6(36^4)=8            [\because \log_aa^x=x]

(f)

\log(100^3)=\log((10^2)^3)

\log(100^3)=\log(10^6)

\log(100^3)=6            [\because \log10^x=x]

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Step-by-step explanation:

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A linear relation is given by the function f (x) = −7x +18 . If (x, 46) is on the function, the value of x is
prohojiy [21]

Answer:

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I also need to know what m∠cdb is
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Answer:

x = 4

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Step-by-step explanation:

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7x + 2 + 17x = 98

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24x = 96

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y + 98 = 180

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3 years ago
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