We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
Answer:
20
Step-by-step explanation:

multiply both sides by 35

divide both sides by 35

For the answer to the question, i<span>f a function uses variables other than x and y for its input and output variables, you take the original equation and solve for the input variable to find the inverse.
The answer is Simply true. But in real life it's false.
I hope my answer helped you.</span>
The picture is too blurry for me even when I try zooming in on it
Answer:
1/2 log2
Step-by-step explanation:
I hope you understand