A rectangle has a width of 10 centimeters. The rectangles length is 4 times it’s width what is the perimeter of the rectangle
1 answer:
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The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, and
are the perpendicular bisectors of
and
respectively and they intersect side
at points
and
respectively.
So, and
Now, <u>according to the postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ =
°
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
Answer:
33 inches
Step-by-step explanation:
The problem above shows a <em>"direct proportion,"</em> which means that when one quantity increases <em>(days)</em>, the other quantity increases<em> (inches of rain).</em>
Step 1: Represent the amount of rain by n.
Step 2: Setup a proportion.
=
(where 14 refers to the number of days in 2 weeks)
Step 3: Cross multiply:
15 x 31 = 14n
465 = 14n
Step 4: Find n by dividing both sides by 14.
n = 33.21
Step 5: Round off to the nearest inch.
n = 33 inches