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3 years ago

Someone please help me it's worth ten points ;))

Mathematics

1 answer:

den301095 [7]3 years ago

5 0

2. is a) = 12 square centimeters
4. is d)=5.5 inches
5. is b)=2.5 inches

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What is the volume of a hemisphere with a diameter of 56.7 in, rounded to the

Vlad1618 [11]

Answer:

Expert Verified

Step-by-step explanation:

the diameter is 57.2 in, then the radius is half that, or 28.6 in. The volume of a sphere is V = (4/3)πr³, and so the volume of this hemisphere is (2/3)πr³

6 0

3 years ago

Below are two parallel lines with a third line intersecting them.

Ulleksa [173]

Answer:

x = 88

Step-by-step explanation:

These angles are same side exterior angles, and when the lines are parallel, same side exterior angles are supplementary

x + 92 =180

Subtract 92 from each side

x+92-92=180-92

x =88

4 0

3 years ago

Read 2 more answers

What is the sum of the measures, in degrees, of the interior angles of a 25-sided polygon?

inna [77]

Exterior angle = 360/25 = 14.4 degrees

internal angle = 180-14.4 = 165.6 degrees

sum of all the angles = 165.6*25 = 4140 degrees answer

4 0

3 years ago

What is negative 5.5, 12/50, and negative 5 3/15 in least to greatest

FinnZ [79.3K]

graph and the pre- image

5 0

3 years ago

Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.

Tasya [4]

Answer:

The answer is " $\bold{\frac{7}{2}}$ "

Step-by-step explanation:

Given value:

$\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0$

Find:

area=?

calculation:

$\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx + \int_{0}^{1} (4x+3x^2-x^3) dx \\\\$

$= -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\= ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\= ( \frac{3}{4}) + (\frac{11}{4})\\\\= \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\$

7 0

3 years ago