Please help this is due soon

Can someone please help me with this; im a lil bit confused.... Q.solve for the values of x in the equation 2x² - 5x - 12 = 0 us

dangina [55]

Answer:

The solutions for x are $x = 4$ and $x = -1.5$ .

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

2x² - 5x - 12 = 0

This means that $a = 2, b = -5, c = -12$

Solution:

$\Delta = (-5)^2 - 4(2)(-12) = 121$

$x_{1} = \frac{-(-5) + \sqrt{121}}{2*2} = 4$

$x_{2} = \frac{-(-5) - \sqrt{121}}{2*2} = -1.5$

The solutions for x are $x = 4$ and $x = -1.5$ .

3 0

3 years ago

Help help helpe help !!!!!!!!!!!!!!!!!!!!!!!!!!!

Mashcka [7]

Answer:

Yes it is a right triangle

Step-by-step explanation:

Brainliest pls

6 0

3 years ago

Mari makes bows for floral arrangements. She uses 1/8 of a yard ribbon for each bow. How many bows can she make from 2 spools th

GuDViN [60]

First, you need to find out how much ribbon she has total. Because there are two spools, you multiply 24 x 2. The answer for that is 48. Then you have to figure out how many bows she can make. Each bow uses 1/8 of a piece of yard of ribbon, so you can divide 48 by 8. Your answer would then be 6 bows.

Here are the equations.

24*2 = X

X/8 = B

Where X represents the yards of ribbon available and B represents the number of bows that Mari can make.

3 0

3 years ago

Is it $34.30 or $38.60?

d1i1m1o1n [39]

Answer:

$38.64

Step-by-step explanation:

Multiply the original price, $48.60 by 0.75 to get the discounted price. This gets you $36.45. Then multiply this by 0.06 to get the sales tax ($2.187) and add this to the sale price (36.45+2.187). This gets you $38.637 which you would round up to $38.64

8 0

4 years ago

18. A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be

avanturin [10]

Answer:

a. =50 ± 4.67

b. =50 ± 4.81

decreasing the sample size increase the margin of error

c. =50 ± 3.51

decreasing the confidence level reduced the margin of error

d. No. because the confidence interval coefficient is gotten from the table of normal distribution of Z value. therefore the confidence interval is only used for normal distributed population

Step-by-step explanation:

given

The sample mean, x, = 50,

the sample standard deviation, s, = 8.

a. Construct a 98% confidence interval for m if the sample size, n, is 20

for a 98% confidence interval of an inﬁnite population, thus for a sample of size N and mean x, drawn from an inﬁnite population having a standard deviation of σ, the mean value of the population is estimated to by:

x± 2.33σ /√N

for a conﬁdence level of 98%, Zc = 2.33 gotten from the table of confidence interval.

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√20) and 50+ ( 2.33*8 /√20)

with 98% conﬁdence in this prediction.

=50 ± 4.67

=45.33 or 54.67

(b) Construct a 98% confidence interval for m if the sample size, n, is 15.

using the same method as above

x± 2.33σ /√N

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√15) and 50+ ( 2.33*8 /√15)

=50 ± 4.81

=45.19 or 54.81

decreasing the sample size increase the margin of error

(c) Construct a 95% confidence interval for m if the sample size, n, is 20. Compare the results to those obtained in part

95% confidence interval =1.96 (gotten from table of confidence coefficient)

using x±1.96 σ /√N

This indicates that the mean value of the population lies between

50- (1.96 *8 /√20) and 50+ (1.96 *8 /√20)

=50 ± 3.51

=46.49 or 53.51

c. decreasing the confidence level reduced the margin of error

(d) Could we have computed the confidence intervals in parts (a)–(c) if the population had not been normally distributed?

No. because the confidence interval coefficient is gotten from the table of normal distribution of Z value. therefore the confidence interval is only used for normal distributed population

7 0

3 years ago