Identify the initial amount in the following exponential function: y = 2.3(1.32)
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The value of constant c for which the function k(x) is continuous is zero.
<h3>What is the limit of a function?</h3>The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.
To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:
Provided that:
Using l'Hospital's rule:
Therefore:
Hence; c = 0
Learn more about the limit of a function x here:
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