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1 year ago

PLS HELP ASAP FIRST CORRECT ANSWER GETS BRAINLEIST

Mathematics

1 answer:

Tasya [4]1 year ago

8 0

Answer:

b ≈ 18.3303

$b = \sqrt{{c}^{2} - {a}^{2} }$

$b = \sqrt{ {19}^{2} - {5}^{2} }$

$b = 18.3303$

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Ling must spend no more than $40.00 on decorations for a party. She has spent $10.00 on streamers and wants to buy bags of ballo

Mumz [18]

A, She can buy from 0 to 12 bags, but no more.

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3 years ago

Three cities form a right triangle on a map. Cities B and C are the furthest apart. If cities A and B are 14 miles apart And cit

nekit [7.7K]

Answer:

26.1miles

Step-by-step explanation:

If three cities A, B and C form a right triangle on a map, and the Cities B and C are the furthest apart, then the distance between cities B and C will be the hypotenuse of the triangle.

If cities A and B are 14 miles apart, then |AB| = 14miles

Also if cities A and C are 22 miles apart, then |AC| = 22miles.

To get |BC| which is the distance between cities B and C, we will use the Pythagoras theorem.

|BC|² = |AB|² + |AC|²

|BC|² = 14²+22²

|BC|² = 196+484

|BC|² = 680

|BC| = √680

|BC| = 26.1miles

This means that cities B and C are 26.1miles apart

7 0

3 years ago

A dance instructor wants 8 costumes to be yellow and 24 costumes to be blue. What is the ratio of blue costumes to yellow costum

Mars2501 [29]

3:1

because...
8/8=1 and 24/8=3

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3 years ago

Solve using the pathagorean theorem

seropon [69]

Answer:

2 sqrt(13)

Step-by-step explanation:

We can find the hypotenuse using the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

4^2 + 6^2 = c^2

16+36 = c^2

52 = c^2

Taking the square root of each side

sqrt (52) = c

sqrt(4*13) = c

2 sqrt(13) = c

4 0

2 years ago

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

3 0

2 years ago

PLS HELP ASAP FIRST CORRECT ANSWER GETS BRAINLEIST​

PLS HELP ASAP FIRST CORRECT ANSWER GETS BRAINLEIST