Answer:
sinA = h/c; sinC = h/a
Step-by-step explanation:
Which pair of equations below is a result of constructing the altitude, h, in Triangle ABC?
sinA= h/c
sinC= h/a
sinA= h/c
sinB= b/c
sinA= b/c
sinC= b/a
Solution:
A triangle is a polygon with three sides and three angles. There are different types of triangles such as right angled, acute, obtuse and isosceles triangle.
In right angle triangle, one angle is 90°. From Pythagoras theorem, the square of the longest side (hypotenuse) is equal to the sum of the square of the two sides.
In right triangle, trigonometric identities are used to show the relationship between the sides of a triangle and the angles.
sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse, tanθ = opposite / adjacent
Therefore in triangle ABC:
sinA = h/c; sinC = h/a
Let
One Number = x
Second Number =x-10
Third Number=x/2
Sum of three numbers is 50
x+x-10+x/2=50
2x-10+x/2=50
Multiply by 2 both sides
2*(2x-10+x/2)=50*2
4x-20+x=100
5x=100+20
5x=120
x=120/5
x=24
One number = x=24
Second number =x-10=24-10=14
Third number= x/2=24/2= 12
Pythagorean Theorem is for triangles not circles.
The equation of a circle is (x - h)² + (y - k)² = radius² where (h, k) is the center.
Plug in your given information and simplify.
(x - (- 1))² + (y - 2)² = (3)²
(x + 1)² + (y - 2)² = 9 is your equation.
Answer:
option 1
Step-by-step explanation:
Corresponding parts of congruent triangles are equal or congruent
B is the righ one i guess