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musickatia [10]
2 years ago
5

Maths- please help me with this Q

Mathematics
2 answers:
Reika [66]2 years ago
5 0

Step-by-step explanation:

please mark me as brainlest

rjkz [21]2 years ago
5 0

Answer:

See below ↓

Step-by-step explanation:

<u>Missing values (a)</u>

  • <u />\left[\begin{array}{ccc}-1&1\\?&?\end{array}\right]
  • Substituting x = 1 and x = -1 respectively in the equation y = x² - 4x
  • \left[\begin{array}{ccc}-1&1\\5&-3\end{array}\right]

<u>Curve which matches the equation</u>

  • On solving y = x² - 4x = x(x - 4) ⇒ x = 0, 4
  • It intersects the x axis at 0 and 4
  • The blue curve is the right one
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Given the graph below, which of the following points would be included in the graph of the inverse of the function?
Svetlanka [38]

Answer : (1,-1)

a line through the points (-1, 1), (0, 2), (1, 3)

To find the point in the graph of inverse function we interchange x  and y values

For point (-1 , 1) , the point on inverse function is (1, -1)

For point (0 , 2) , the point on inverse function is (2, 0)

For point (1 , 3) , the point on inverse function is (3, 1)

so (1,-1) will be  included in the graph of the inverse of the function

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Identify the solution set of each equation or inequality using the given replacement set
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I believe the answer is C
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The furniture store where Jada's sister works bought a table for $200 and sold it for $350. What percentage was the markup? I wa
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Answer:

divide 350 by 200

Step-by-step explanation:

3 0
3 years ago
pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base
kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

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We expect your answer is supposed to be Step 4.

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V+27=117
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v=90
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