Lol sry nobody came to help you earlier...
honestly u shoould just put all the values in a calculator.
The second one, fourth one, and last one
Answer:
208 ft
Step-by-step explanation:
in order to do this we need to find the area of the retangle:
(l x w) 14x20= 280ft
then the area of the rectangle:
a^2 + b^2 = c^2 ( hypotenus lenght )
c= 8.5
now we can plug in to find the area of the triangle, which is 12 (11.99)
then the area of the trapezium= 60
finally we can find the answer
280 - (60+12)= 208 ft :)
Answer:
f(x)=4x^2
f(2)=4(2)^2
f(2)=4(4)
f(2)=16
2. g(x)=4*2^x
g(2)=4*2^2
g(2)=4*4
g(2)=16
f(2)=g(2)
Both is equal to 16
I hope this help you :)
Step-by-step explanation:
Thw answer would be 0.007
Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=
⇒ 
Now let 
∵ 
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.