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3 years ago

what is 13 approximated to the nearest tenth? Answers: A. 3.5 B. 3.6 C. 3.7 D. 3.8

1 answer:

3 0

$\sqrt{13}\approx3.605551....\approx3.6\\\\Answer:B$

$A.\ 3.5^2=12.25\\\\B.\ 3.6^2=12.96\\\\C.\ 3.7^2=13.96\\\\D.\ 3.8^2=14.44\\\\nearest\ 13\ is\ 12.96=3.6^2$

$Answer:3.6\ (B)$

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John Simone is buying a used car for a total cost of $11,805.00. He’s making a down payment of $1,500.00 and borrowing the remai

balu736 [363]

Answer:

Step-by-step explanation:

Given that John Simone is purchasing a used car for 11805 dollars.

Down payment = 1500

Net loan amount = 11805-1500 = 10305

Equal monthly instalments he paid = 343 dollars

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For 3 years rate of interest should be 12.2%

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3 years ago

13x-11 +18x15+ 4x+1=180°

BARSIC [14]

Answer:

x = - 80/17, or x = - 4 $\frac{12}{17}$

Step-by-step explanation:

13x-11 +18×15+ 4x+1=180°

<=> (13x + 4x) + (18×15+ 1 - 11)=180°

<=> 17x + 260 =180

<=> 17x = 180 - 260

<=> 17x = - 80

<=> x = - 80/17

<=> x = - 4 $\frac{12}{17}$

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3 years ago

What is the standard form of the equation of the circle in the graph?

jonny [76]

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3 years ago

Is (4,3) a solution to the inequality graph below? Why or why not? I need help plz don’t upload files

Studentka2010 [4]

Answer:

yes

Step-by-step explanation:

Go to x=4 and y= 3

It is in the shaded area to it is a solution

7 0

3 years ago

Find the equation of a line that passes through (-5,4) and us parallel to y=-6/7x+3

irina [24]

Given:

The given equation of line is

$y=-\dfrac{6}{7}x+3$

To find:

The equation of line that passes through (-5,4) and is parallel to the given line.

Solution:

Slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

We have,

$y=-\dfrac{6}{7}x+3$ ...(ii)

On comparing (i) and (ii), we get

$m=-\dfrac{6}{7}$

Slope of given line is $m=-\dfrac{6}{7}$ .

Slope of parallel lines are same. So, slope of parallel line is $m=-\dfrac{6}{7}$ .

The required line passes through (-5,4) with slope $m=-\dfrac{6}{7}$ . So, the equation of line is

$y-y_1=m(x-x_1)$

$y-4=-\dfrac{6}{7}(x-(-5))$

$y-4=-\dfrac{6}{7}(x+5)$

$y-4=-\dfrac{6}{7}x-\dfrac{30}{7}$

Adding 4 on both sides, we get

$y=-\dfrac{6}{7}x-\dfrac{30}{7}+4$

$y=-\dfrac{6}{7}x+\dfrac{-30+28}{7}$

$y=-\dfrac{6}{7}x-\dfrac{2}{7}$

Therefore, the correct option is a.

8 0

3 years ago