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Ivan
3 years ago
15

PLEASE HELP ME!! this is due tonight and i really need help with this so i can do other assignments

Mathematics
2 answers:
Mamont248 [21]3 years ago
5 0

Answer:

64cm² I think :) if u get it wrong dont blame it on me.

Nataliya [291]3 years ago
4 0

Answer:

64 cm^2

Step-by-step explanation:

The area of a square can be calculated by A = s^2 (Area = side squared aka the side multiplied by itself)

A = s^2

= 8^2 (8 x 8)

= 64 cm^2

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Help please its for school
Alex

Answer:

68.302

Step-by-step explanation:

68302/1000=68.302

hope this helps :)

8 0
3 years ago
Read 2 more answers
Perimeter of an isosceles triangle is 35 cm if the length of a the congruent sides is 3 times the length of the third side what
Dimas [21]

Let the length of the shortest side = x

The two longer sides that are equal = 3x

The are two equal longer sides, so their total is 3x + 3x = 6x

3x+ 3x + x= 35  Collect like terms on the left

7x = 35               Divide by 7  on both sides

x = 35/7

x = 5

Answer

Two long sides -- 15 cm each

Shortest side -- 5 cm

5 0
3 years ago
What is the least common multiple of 8 and 12?<br> 96<br> 24<br> 48
Aleonysh [2.5K]

Answer:

B. 24 :)

Step-by-step explanation:

I hope this helps!

6 0
3 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
5.6 as an improper fraction simplified?
Phoenix [80]
As a fraction, it would be 5 6/10. Then you multiply the denominator by the whole number 5x10 and add the numerator. So,
10X5+6=56
56/10
divide by 2
28/5 is the simplified version
8 0
3 years ago
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