PLEASE PLEASE PLEASE PLEASE (5'1, 5'2, 5'3, 5'4, 5'5, 5'6, 5'7, 5'8, 5'9, 5'9, 5'10, 5'11, 5'12) PLEASE FIND THE ABSOLUTE DEVIAT
crimeas [40]
Answer:
Answer:
A. mean: 5.75
B. 1.8958
Thank you! Please mark me brainliest so that I get encouraged to answer more great questions like this one!
Answer:
3x1
4(x-2)
3x+2
4(8-0)
Step-by-step explanation:
Answer:
90
Step-by-step explanation:
Answer:
0.59
Step-by-step explanation:
5/2.95=1/x
x=0.59
I think its the answer
Sorry if its wrong cause I'm dumb too
The <em>correct answers</em> are:
5x²+70x+245 ≥ 1050; and
Yes.
Explanation:
Let x be the width of the tablet. Since the width of the TV is 7 inches more than the tablet, the width of the TV would be x+7.
The length of the TV is 5 times the width; this makes the length 5(x+7) = 5x+35.
The area of the TV would be given by
(x+7)(5x+35).
Since Andrew wants the area to be at least 1050, we set the expression greater than or equal to 1050:
(x+7)(5x+35) ≥ 1050
Multiplying this, we have:
x*5x+x*35+7*5x+7*35 ≥ 1050
5x²+35x+35x+245 ≥ 1050
Combining like terms,
5x²+70x+245 ≥ 1050
To see if 8 is a reasonable width for the tablet, we substitute 8 for x:
5(8²)+70(8)+245 ≥ 1050
5(64)+560+245 ≥ 1050
320+560+245 ≥ 1050
1125 ≥ 1050
Since this inequality is true, 8 is a reasonable width.
