Answer:
7
Step-by-step explanation:
V = 4/3πr^3V = 4/3 (π) (6.5)^3
V = 366.1666π (6 repeat)
answer is 366.16 π (3rd choice)
Answer:
Domain = -2, range = -5
Domain =>0, range = 0
domain = 2, range = 5
let y =>f(x)
It can be seen that Function can be linear having common difference 2
F(x) = 2x + 1 for x>0
is satisfied for above values
let's check
F(2) = 2(2)+1 = 4+1 = 5 As given
For x<0 , F(x) = 2x -1
f(-2)= 2(-2) -1= -4-1= -5 As given
For X= 0, F(x)= 2x
So , F(0) = 0 As given
Answer: 529 students
Step-by-step explanation:
To solve this, we will be using the formula for finding averages:
> (total sum of student weights) ÷ (total sum of students) = (average of student weights)
Plugging in the values that are given in the problem, you get:
> 16,293.2 ÷ x = 30.8
Where x is equal to the total sum of students. From here, it's a simple equation to isolate x, and find out what numerical value x is equal to. In case you are unsure how to do this, I've created a clear step by step process for how to do this (NOTE: The slash represents division, while the asterisk represents multiplication.):
> 16,293.2 / x = 30.8
> (16,293.2 / x) * x = (30.8) * x
> 16,293.2 = 30.8 * x
> (16,293.2) / 30.8 = (30.8 * x) / 30.8
> 529 = x
In total, there are 529 students in the school.
