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Lelechka [254]
2 years ago
9

Josiaanswer this is it josia the question

Mathematics
1 answer:
makkiz [27]2 years ago
3 0

Answer:

6? i am soooo confused

Step-by-step explanation:

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Ernest borrowed $1000 from the bank. The interest rate is 30% and he borrowed it for 9 months. How much will he owe the bank?
Fudgin [204]

The total amount Ernest owes the bank after 9 months is $1,225.00

How many months of interest would be paid?

The fact the loan was taken for nine months means that the borrower, Ernest needs to pay interest for nine months, in other words, we would time-apportion the annual interest of 30% to determine the 9-month interest as shown below:

9-month interest rate=30%*9/12

9-month interest rate=22.50%

The amount Ernest is owing the bank is the principal borrowed plus the interest for  9 months as computed below:

total amount owed after 9 months=$1000*(1+22.50%)

total amount owed after 9 months=$1000*1.2250

total amount owed after 9 months=$1,225.00

Find out more about borrowing on:brainly.com/question/28188613

#SPJ1

5 0
2 years ago
Which of the following values best approximates the length of C in triangle ABC where C=
irinina [24]

Answer:

The correct answer is D 46.3644



8 0
2 years ago
Find the LCM of 8, 12, and 26
Dafna1 [17]
312 is the LCM for this set
3 0
3 years ago
Can someone explain to me how to do this
rusak2 [61]

rank | 1st | 2nd |TOTAL
------|-----+-------|----------
a     | 6   +    9   |  =15
b     | 7   +   3    | =16
c     | 9   +   7    | =23
d     | 6   +   7    | =22
e     | 8   +  1     | =?


If you add the 1st in line a (6) and you add it to the 1st in line b (7) + the 2nd in line b (3) you get 16. Repeat the same logic/pattern to all c,d..
This is the pattern to all this puzzle;

So the before last term is :  9+6+7 = 22
and the last term : 6+8+1 = 15


7 0
3 years ago
Simplify: (sin θ − cos θ)^2 − (sin θ + cos θ)^2 A) −4sin(θ)cos(θ) B) 2 C) sin^2 θ D) cos^2 θ
N76 [4]

Answer:

-4sinθcosθ

Step-by-step explanation:

Note:

1. (a + b)^2 = a^2 + 2ab + b^2

2. (a - b)^2 = a^2 - 2ab + b^2

3. sin^2θ + cos^2θ = 1

(sinθ -cosθ)^2 - (sinθ + cosθ)^2

= sin^2θ - 2sinθcosθ + cos^2θ - (sin^2θ + 2sinθcosθ + cos^2θ)

= sin^2θ + cos^2θ - 2sinθcosθ - (sin^2θ + cos^2θ + 2sinθcosθ)

= 1 - 2sinθcosθ - (1 + 2sinθcosθ)

= 1- 2sinθcosθ -1 - 2sinθcosθ

= - 2sinθcosθ - 2sinθcosθ

= -4sinθcosθ

3 0
3 years ago
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