~Hello there! ^_^
Your question: What place value does 3 have in 4,235,100..?
Your answer: Lets solve this!
So, the number 3 is standing in 10 thousands place.
Simple...
The place value of 3 is 30,000.
Voila! Your answer!
Hope this helps~
Answer:
B (5, 13)
Step-by-step explanation:
9x + 4y = 97
9x + 6y = 123
To solve by elimination, we want to <em>eliminate</em> a variable. To do this, we must make one variable cancel out.
First, we can see that both equations have 9x. To cancel out x, we must make <em>one</em> of the 9x's <em>negative</em>. To do this, multiply <em>each term</em> in the equation by -1.
-1(9x + 6y = 123)
-9x - 6y = -123
This is one of your equations. Set it up with your other given equation.
9x + 4y = 97
-9x - 6y = -123
Imagine this is one equation. Since every term is negative, you will be subtracting each term.
9x + 4y = 97
-9x - 6y = -123
___________
0x -2y = -26
-2y = -26
To isolate y further, divide both sides by -2.
y = 13
Now, to find x, plug y back into one of the original equations.
9x + 4(13) = 97
Multiply.
9x + 52 = 97
Subtract.
9x = 45
Divide.
x = 5
Check your answer by plugging both variables into the equation you have not used yet.
-9(5) - 6(13) = -123
-45 - 78 = -123
-123 = -123
Your answer is correct!
(5, 13)
Hope this helps!
The answer is 5.5 because 66/12= 5.5, hope this helps..
Answer:
![y\leq 4](https://tex.z-dn.net/?f=y%5Cleq%204)
Step-by-step explanation:
Start with the given
![2y\leq 8\\](https://tex.z-dn.net/?f=2y%5Cleq%208%5C%5C)
Divide the two on both sides to get
![y\leq 4](https://tex.z-dn.net/?f=y%5Cleq%204)
Answer:
Step-by-step explanation:
Given that you and a friend play a game where you each toss a balanced coin.
If the upper faces on the coins are both tails, you win $1;
if the faces are both heads, you win $2;
if the coins do not match (one shows a head, the other a tail), you lose $1 (win (−$1)).
Let Y be the amount won
Then Y can take values as 1,2 and -1
![P(Y=1) =P(TT) = 0.25\\P(Y=2) = P(HH) = 0.25\\P(Y=-1) = P(HT)+P(TH) = 0.5](https://tex.z-dn.net/?f=P%28Y%3D1%29%20%3DP%28TT%29%20%3D%200.25%5C%5CP%28Y%3D2%29%20%3D%20P%28HH%29%20%3D%200.25%5C%5CP%28Y%3D-1%29%20%3D%20P%28HT%29%2BP%28TH%29%20%3D%200.5)
The above is the probability distribution for Y.