My little sister needs help in this and I don't remember.

Mathematics

1 answer:

Anna71 [15]1 year ago

7 0

You have to have the same denominator for both fractions, so I would multiply 3/4 by 3 that would give you 9/12 and the other one is 7/12. This means that the final answer would be 9/12>7/12.

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Find the solution set of 5/y+4=3/y-2

GaryK [48]

Answer:

y=-1/3

Step-by-step explanation:

first combine like terms:

5/y-3/y=-2-4

2/y=-6

now multiply y on both sides:

2=-6y

solve the equation

y=-1/3

4 0

2 years ago

Read 2 more answers

BRAINLIEST ASAP! PLEASE HELP ME :)

Irina-Kira [14]

Answer:

○ $\displaystyle 25\%$

Step-by-step explanation:

3 → 13 − 16

$\displaystyle \frac{Number\:of\:desired\:[favourable]\:outcomes}{Total\:number\:of\:possible\:outcomes} \\ \\ \frac{3}{12} = \frac{1}{4} = 25\%$

I am joyous to assist you anytime.

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2 years ago

Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.

vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

$\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}$

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

$\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}$

So, it becomes,

$\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ$