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2 years ago

Edmond buys 4/5 of a kilogram of butterscotch chips and 5 kilograms of milk chocolate chips.

Mathematics

1 answer:

Vika [28.1K]2 years ago

8 0

He spent $5.80.

1 x 4/5 = 0.8
1 x 5 = 5

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The area of the triangle below is 2/5 square foot. What is the length in feet of the base of the triangle?

solmaris [256]

Answer:

C) 2/3

Step-by-step explanation:

8 0

3 years ago

Si a un múltiplo de 8 le sumo 1 obtengo un múltiplo de 5, ¿qué múltiplos de 8

Simora [160]

Answer:

24, 64

Step-by-step explanation:

If I add 1 to a multiple of 8 I get a multiple of 5, what multiples of 8

meet the condition? (Mention at least 2 of them)

3 x 8 + 1 = 25

8 x 8 + 1 = 65

4 0

3 years ago

How do I do this problem ?

katrin2010 [14]

Y=13 Because a line equals 180. 180-11=169/13=13
x=8 because 180+22=202-4=198/11=18

3 0

3 years ago

The measure of position called the midquartile of a data set is found using the formula StartFraction Upper Q 1 plus Upper Q 3 O

irinina [24]

Answer:

35.25

Step-by-step explanation:

Give the data set:

23 37 49 34 35 41 40 26 32 22 38 42

We are expected to calculate the midquartile of the given data set.

22 23 26 32 34 35 37 38 40 41 42 49

First step is to find the lower quartile which comprises of

22 23 26 32 34 35

Here the Q1 is (26+32)/2 = 58/2= 29

Second step to find the upper quartile which comprises of

37 38 40 41 42 49

Here the Q3 is (40+41) /2 = 81/2 = 41.5

Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5

= (29+41.5)/2

= (70.5) /2 = 35.25

8 0

3 years ago

The height h(n) of a bouncing ball is an exponential function of the number n of bounces.

Digiron [165]

Answer:

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

$h = h_{o}\cdot r^{n-1}$ , $n \in \mathbb{N}$ , $0 < r < 1$ (1)

Where:

$h_{o}$ - Height reached by the ball on the first bounce, measured in feet.

$r$ - Decrease rate, no unit.

$n$ - Number of bounces, no unit.

$h$ - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

$r = \frac{h_{1}}{h_{o}}$ (2)

Where $h_{1}$ is the height reached by the ball on the second bounce, measured in feet.

If we know that $h_{o} = 6\,ft$ and $h_{1} = 4\,ft$ , then the expression for the height of the bouncing ball is:

$h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

5 0

3 years ago

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