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2 years ago

Whats the simplest form of 6 /18

Mathematics

2 answers:

MissTica2 years ago

8 0

Answer:

What is 6/18 Simplified? - 1/3 is the simplified fraction for 6/18.

Step-by-step explanation:

Nataliya [291]2 years ago

7 0

Answer:

3/9

Step-by-step explanation:

6 divided by 2 = 3

18 divided by 2 = 9

So that equals 3/9

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How to solve equations with the substitution method

Paul [167]

Answer:

In a system, the substitution method is one of the 3 main ways to solve a system and can be very efficient at times.

<u>Skills needed: Systems, Algebra</u>

Step-by-step explanation:

1) Let's say we are given two equations below:

$y=4x \\ 4x-5y=-32$

We can use substitution here by substituting in for $y$ in the second equation. This means we put in $4x$ for $y$ in the 2nd equation so we only have $x$ variables in the equation, allowing us to solve for $x$ .

2) Solving it out:

$1) 4x-5(4x)=-32 \\ 2) 4x-20x=-32 \\3) -16x=-32 \\4)x=2\\5)y=4x = 4(2) = 8 \\ 6)y=8$

We essentially substitute in that value as seen in step 1. Steps 2 and 3 are just simplifying the left side and allowing for us to solve. Step 4 is where we divide by -16 on both sides to solve for x. Step 5 and 6 show us solving for y using the value for x. We get $x=2,y=8$

5 0

1 year ago

Read 2 more answers

Which expression is equivalent to Cosine (StartFraction pi Over 12 EndFraction) cosine (StartFraction 5 pi Over 12 EndFraction)

alekssr [168]

Answer:

A. cos( $-\frac{\pi}{3}$ )

Step-by-step explanation:

Typed the all the expressions into desmos and picked the ones that matched

7 0

2 years ago

Read 2 more answers

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$