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Shalnov [3]
3 years ago
13

sophia has 100 cookies. she wants to give 15 each among 5 people. can she give 15 cookies among 5 people with her 100 cookies? e

xplain why or why not.
Mathematics
2 answers:
Alex17521 [72]3 years ago
7 0
She can give 15 cookies to 5 people.
15x5=75
75 is less than 100, so she can give out cookies and still have 25 left over.
Andrews [41]3 years ago
3 0

Answer:

Yes, she can, because if every person gets 15 cookies that's 75 cookies in total which means she will have 25 cookies leftover. Sophia could even give everyone 20 cookies but have no cookies leftover.

Step-by-step explanation:

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<u>Testing the hypothesis</u>, it is found that since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

At the null hypothesis, it is tested if the <u>proportion is of 0.5</u>, that is:

H_0: p = 0.5

At the alternative hypothesis, it is tested if the <u>proportion is different of 0.5</u>, that is:

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The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

In which:

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In this problem, the parameters are given by:

p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482

The value of the test statistic is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}

z = \frac{0.5482 - 0.5}{\sqrt{\frac{0.5(0.5)}{881}}}

z = 2.86

Since we have a <u>two-tailed test</u>(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

Looking at the z-table, z = -2.86 has a p-value of 0.0021.

2(0.0021) = 0.0042

Since the <u>p-value of the test is 0.0042 < 0.01</u>, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

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