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2 years ago

6

G[f(x)] if g(x) = x2 and f(x) = x + 3.

1 answer:

lesantik [10]2 years ago

7 0

(x+3)2
you need to substitute x in function g(x) with the entire function of f(x)

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Mr wellborn arrives at work at 8:40 a.m he leaves for work 50 minutes before he arrives at what time does Mr wellborn leave for

Yuri [45]

Mr Wellborn arrives at work at 7:50 am. If you take 60 minutes away from 8:40 its 7:40 but take away 10 minutes and its 7:50.

8 0

3 years ago

Simplify -23b4+(-7b4)

Rzqust [24]

-30b4 would be your answer.

Hope I helped!

3 0

3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

2 years ago

Find the ratios for the trig functions below<br><br> sin A =<br><br> cos C =

kondor19780726 [428]

Answer:

Sin A: 35/37

Cos C: 35/37

Step-by-step explanation:

Sin A: 35/37

Cos C: 35/37

Using acronym SohCahToa we know

Sin is Opposite/Hypotenuse

Cos is Adjacent/Hypotenuse

With each problem we mark by the letter given to create adjacent side.

I hope this helps!

5 0

2 years ago

Please help me this is urgent! Both need an answer.

dolphi86 [110]

My answer is B and A that's my answer

3 0

3 years ago