Just divide it and you will get the answer
Step-by-step explanation:
First, distribute the -4 to the parenthesis:
24a-22=-4+24a
Add 22 to both sides:
24a-22+22=-4+22+24a
Simplify:
24a=18+24a
Subtract 24a from both sides:
24a-24a=18+24a-24a
Simplify:
0=18
hope this helps :)
Answer:
Length = Width = 7 cm
Step-by-step explanation:
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
