F g(x) = 2x + 2, find g(a + h) - g(a).

Mathematics

1 answer:

Tresset [83]3 years ago

4 0

Answer: 2h

Step-by-step explanation:

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The focus of a parabola is (-10, -7), and its directrix is x = 16. Fill in the missing terms and signs in the parabola's equatio

avanturin [10]

Answer: (y-3)^2= 52(x+7)

The focus is (-10, -7) and the directrix is x=16. The y-coordinate of the vertex should be same as the focus(k=-7). Then the x-coordinate of the vertex would be:
p + (-10)= 16 - p
2p= 16 + 10
p=26/2= 13

The x-coordinate of the vertex would be:
h= p+ (-10)
h= 13 - 10= 3

The vertex coordinate would be: (h, k)= (3, -7)
For a vertex (h, k), the formula for equation would be
(y-k)^2=4 p(x-h)
(y-3)^2= 4*13(x--7)
(y-3)^2= 52(x+7)

7 0

3 years ago

Need help please I would be grateful

Xelga [282]

Answer:

The correct answer is given by option A.

Step-by-step explanation:

A function is said to be increasing for intervals of x in which the values of y are increasing, that is, it trends upwards, and decreasing for intervals of x in which the values of y are decreasing, that is, it trends downwards.

In this question:

It trends upwards from the start, at negative infinity, until 0.

It trends downwards from 0, until the end, at positive infinity.

So the correct answer is given by option A.

7 0

3 years ago

Fill out the following chart to find the temperatures for t = 12 (noon) and t = 24 (midnight). (2 points: 1 point for each row)

sergey [27]

Part.1
Given equation:
C(t) = -0.30 (t – 12)² + 40

For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2

For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40

For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2

Part.2
Graph of the equation is given in the attachment.

Part.3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32

Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104