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Jobisdone [24]
3 years ago
12

There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin

d the maximum no. of items possible in each packet
Mathematics
1 answer:
Ksju [112]3 years ago
4 0

To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.

The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.

Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.

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jeyben [28]
12 = 3/4 * x
12 ÷ 3/4 = x
12 * 4/3 = x
48/3 = x
16 = x

Answer: The whole set is 16 counters
5 0
3 years ago
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Simplify the expression - 3+(-2/5)
xxMikexx [17]

Answer:

The answer is -17/5

Step-by-step explanation:

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6 0
3 years ago
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Can someone help me out
Sophie [7]

Firstly, you want to multiply (f^4)^2. \frac{2*f^8*f^2}{8f^{12}}


Next, multiply everything on the numerator. \frac{2f^{10}}{8f^{12}}


Next, divide. \frac{2f^{10}}{8f^{12}}=\frac{1}{4} f^{-2}


Now remember that f^-2 = (1/f^2), so just convert the negative powered exponent to that, and your answer will be \frac{1}{4f^2}

6 0
3 years ago
First to answer gets something good ;)
lesya [120]

Answer:

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7 0
3 years ago
An open rectangular box is 4 feet long and has a surface area of 20 square feet. Find the dimensions of the box for which the vo
sweet-ann [11.9K]
SA=2H(L+W)+LW for open box
20=2H(4+W)+4(W)
distribute
20=8H+2WH+4W
divide both sides by 2
10=4H+WH+2W
solve for 1 variable, pick W
10-4H=WH+2W
10-4H=W(H+2)
(10-4H)/(H+2)=W

V=LWH
subsitute 4 for V, subsitute H for H and (10-4H)/(H+2) for W
V=(4)(H)(10-4H)/(H+2)
V=(40H-16H²)/(H+2)
find max value
take deritivitive of this thing
V'=-16(H²+4H-5)/((H+2)²)
using sign chart
sign changes from positive to negative at H=1

so at H=1
find W

W=(10-4H)/(H+2)
W=2

the dimeionts are

length=4ft
width=2ft
height=1ft
(the volume is 8 cubic feet)
3 0
3 years ago
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