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ozzi
3 years ago
14

Which of the following are exterior angles check all that apply?

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

The exterior angles on this diagram are angle 4 and angle 2.

We can see this because an exterior angle is the angle that forms a straight line with an interior angle, so that 180 - [interior angle] = [exterior angle].

Therefore, angles 4 and 2 are the only angles that form straight lines with interior angles, so they are thus the exterior angles.

I hope this helps!

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0.5 is the decimal equivalent to 1/2
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3 years ago
Read 2 more answers
-4x + 7(x + (-2)) > -18
professor190 [17]
-4x+7x-14
3x-14>-18
3x>-4
X>-4/3
3 0
4 years ago
The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class
alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0
3 years ago
The answer and how to do it.
Kruka [31]

let x = orginal price of the shorts

$21 = x(100%-20%) * 1.05

$21 = x(80%) * 1.05

$21 = 0.8x * 1.05

Subtract 1.05 from both sides

$19.95 = 0.8x

Divide 0.8 from both sides

$24.9375 = x

So the orginal price of the shorts are about $24.94

4 0
3 years ago
Please help with this question
ELEN [110]

Answer:

r^2 * 1/s^4 * t^5

Step-by-step explanation:

r^2 * 1/s^4 * t^5

s^-4 = 1/s^4

7 0
3 years ago
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