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HACTEHA [7]
3 years ago
14

When 27 times x squared times z all over negative 3 times x squared times z to the fourth power is completely simplified, the ex

ponent on the variable z is _____.
Numerical Answers Expected!


I have attached a picture of the problem so it's easier to read.

Mathematics
2 answers:
Olin [163]3 years ago
5 0

Answer:

The exponent on the variable z is (-3).

Step-by-step explanation:

Exponent: A quantity representing a power upto which a number of expression is raised often written in superscript of number or an expression..

Given expression:

\frac{27x^2z}{-3x^2z^4}

Using identity : \frac{a^m}{a^n}=a^{n-m}

=\frac{27(x)^{2-2}(z)^{1-4}}{-3}=-9x^0z^{-3}

The exponent on the variable z is (-3).

snow_lady [41]3 years ago
4 0
Isolate z by itself:

\frac{z}{z^4}

To simplify variables with powers, subtract the smaller power from the bigger power:

4 - 1 = 3
\frac{z}{z^4} = \frac{1}{z^3} = z^{-3}

The exponent will be -3.
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Round your answer to the nearest hundredth.
choli [55]

Answer:

9

Step-by-step explanation:

I used tan but there's probably an easier way to do this but 4*tan(20)=8.94 then round it up to 9

8 0
2 years ago
Read 2 more answers
Please help me out!!!!!
olga2289 [7]

Answer:

D. 9

Step-by-step explanation:

9 is the degree of polynomial

3 0
2 years ago
Brian needs to start planning for an upcoming move. He is choosing two different size boxes to pack the majority of his stuff. T
GenaCL600 [577]

Solution:

Given,

Volume of the-

First cube box=1728 in³

Second cube box=13824in³

We know that volume of cube =a³

So for the first box

a³= 1728 in³

a= 12 in

Now, surface area of the first box

6a²= 6×(12)²

= 864 in²

and for the second box

b³= 13824 in³

b= 24 in

Now, the surface area of the second box

6b²= 6×(24)²

= 3456 in²

Now, the ratio of the surface area of first box to the second box will be

864:3456

=1:4

The surface area of the larger of two boxes is

3456 in²

5 0
3 years ago
At a football stadium, 4% of the fans in attendance were teenagers. If there were 120 teenagers at the football stadium, what wa
Law Incorporation [45]
1200 divided by 4%= 3000
3 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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