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HACTEHA [7]
3 years ago
14

When 27 times x squared times z all over negative 3 times x squared times z to the fourth power is completely simplified, the ex

ponent on the variable z is _____.
Numerical Answers Expected!


I have attached a picture of the problem so it's easier to read.

Mathematics
2 answers:
Olin [163]3 years ago
5 0

Answer:

The exponent on the variable z is (-3).

Step-by-step explanation:

Exponent: A quantity representing a power upto which a number of expression is raised often written in superscript of number or an expression..

Given expression:

\frac{27x^2z}{-3x^2z^4}

Using identity : \frac{a^m}{a^n}=a^{n-m}

=\frac{27(x)^{2-2}(z)^{1-4}}{-3}=-9x^0z^{-3}

The exponent on the variable z is (-3).

snow_lady [41]3 years ago
4 0
Isolate z by itself:

\frac{z}{z^4}

To simplify variables with powers, subtract the smaller power from the bigger power:

4 - 1 = 3
\frac{z}{z^4} = \frac{1}{z^3} = z^{-3}

The exponent will be -3.
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Paha777 [63]

Answer:

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Step-by-step explanation:

Given:

f(x)=2x^2+4\\\\g(x)=\sqrt{3x^3}

Required:

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Solution:

let f(g(x))=f(X), where X=g(x)

so f(X)=2X^2+4

put X=g(x)=\sqrt{3x^3}, we get

f(g(x))=2(\sqrt{3x^3} )^2+4

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3 years ago
the hoover dam is 725 feet tall. how long would it take an object to fall from the top to the base of the dam? round the answer
Alinara [238K]

Answer:

45.05 seconds

Step-by-step explanation:

Use the formula: d = vi t + \frac{1}{2} at^{2}

d = distance      vi = initial velocity (m/s)    

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m is meters and s is seconds. They are units of measurement so leave them be.

Assuming the object is simply dropped, the initial velocity is 0 since the object was not moving before it was dropped.

The distance is 725 feet, which is 220.98 meters.

The acceleration is 9.81m/s^{2} since that is the acceleration of Earth's gravity, aka free fall.

Time is what we are trying to find so just leave it as the variable t.

So plug the values into the equation:

220.98m = (0)(t) + \frac{1}{2} (9.81m/s^{2})(t)

220.98m = (4.905m/s^{2})(t)

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Answer:

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