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hodyreva [135]
4 years ago
15

How do you slove this

Mathematics
1 answer:
GaryK [48]4 years ago
5 0
No she didn't write it correct.

it is soppose to be like this 72,506.
seventy-two thousand five hundred and six
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Sam kept his account open for 2 days.
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The kingston review (kr) is testing a new gmat question. the kr wants to determine what proportion of test-takers will answer th
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Can someone pls tell me the answer
sleet_krkn [62]

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Step-by-step explanation:

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3 years ago
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The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 m
rusak2 [61]

Answer:

0.59375

Step-by-step explanation:

In a uniform distribution the probability that the time t is greater than any given value, X, is:

P(t\geq X)=1-\frac{X}{b-a}

In this problem, the limits of the distribution are a = 0 and b = 8 minutes.

For X =3.25 minutes:

P(t\geq 3.25)=1-\frac{3.25}{8-0} \\P(t\geq 3.25)=0.59375

The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is 0.59375.

8 0
4 years ago
Which of the following points could be added to the graph f(x)=-|x+3| to keep the graph a function?
sasho [114]

None of the points could be added to the graph f(x)=-|x+3| to keep the graph a function

<h3>How to determine the point?</h3>

The equation of the function is given as:

f(x) = - |x + 3|

The points are given as:

(0, 3) and (-3, -6)

When x = 0, we have:

f(0) = - |0 + 3|

f(0) = -3 --- different y value from (0, 3)

When x = -3, we have:

f(-3) = - |-3 + 3|

f(-3) = 0 --- different y value from (-3, -6)

This means that the x values point to different y values (this does not represent a function)

Hence, none of the points could be added to the graph f(x)=-|x+3| to keep the graph a function

Read more about functions and relations at:

brainly.com/question/2328150

#SPJ1

6 0
2 years ago
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