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2 years ago

Find the perimeter and area of a regular hexagon with side lengths of 8 and an apothem of 9.

1 answer:

7 0

The perimeter and area of a regular hexagon with side length of 8 and apothem of 9 are 48 units and 216 units² respectively.

<h3>What is a regular hexagon?</h3>

A regular hexagon is a polygon with 6 sides and the angles are congruent.

The perimeter of the hexagon is the sum of the whole sides. Therefore,

side length = 8 units

apothem = 9 units

perimeter = 8 × 6 = 48 cm

The area of the hexagon can be calculated as follows:

area = 1 / 2 pa

where

p =perimeter

a = apothem

Therefore,

area = 1 / 2 × 48 × 9

area = 432 / 2

area = 216 units²

learn more on hexagon here: brainly.com/question/15392522

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3 years ago

Read 2 more answers

F(x) = x2 - 8x - 20<br> What is the axis of symmetry, vertex, and y intercept

igor_vitrenko [27]

1. vertex is -4 because:

x^2-8x-20,

a=1, b=-8 , c=-20

use vertex form! -b/2a = -8/2(1) = -8/2 = -4.

2. axis of symmatry is the x which is also -4. The same steps go for the second one.

3. y intercept, I think the answer is -20. Im not sure for this one.

IF YOU LIKE THIS ANSWER PLEASE GIVE ME BRAINLIEST.

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