Question

Find the derivative of y = 1/ (3x^3) with steps

Answer 1

Answer:

$- 9 {x}^{ - 4}$

Step-by-step explanation:

$y = \frac{1}{ {3x}^{3} } = {3x}^{ - 3}$

$y = < - 3 \times 3 > {x}^{ - 3 - 1} \\ = - 9 {x}^{ - 4}$