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2 years ago

BCD and EFG are shown below. Which of the following statements is true? Look at picture.

Mathematics

2 answers:

ELEN [110]2 years ago

8 0

Answer:

(b) ∠EGF ≅ ∠BDC

Step-by-step explanation:

Angles D and G are both marked with double arcs, indicating they are congruent:

∠EGF ≅ ∠BDC

Other choices:

BD is the short segment between the marked angles. It has no "decoration." EF is the longer segment with a single hash mark decoration. These are not corresponding parts, so are not congruent. There is no right angle in these triangles, so the Pythagorean theorem is not applicable.

CD is the longest side, with no decoration. EF is the middle-length side with a single hash mark decoration. These are not corresponding sides.

Nikitich [7]2 years ago

8 0

Answer:

I don't know I'm sorry soo just try to work it out if u don't know how than ask someone you know okay, ur welcome.

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What is the solution to | 2x-4| >8?

Serga [27]

$| 2x-4| \ \textgreater \ 8 \\ \\ 2x - 4 \ \textgreater \ 8 \ , \ -(2x - 4) \ \textgreater \ 8 \ / \ break \ problem \ into \ 2 \ equations \\ \\ first \ equation \\ \\ 2x \ \textgreater \ 8 + 4 \ / \ add \ 4 \ to \ each \ side \\ \\ 2x \ \textgreater \ 12 \ / \ simplify \\ \\ x \ \textgreater \ \frac{12}{2} \ / \ divide\ each \ side \ by \ 2 \\ \\ x \ \textgreater \ 6 \ / \ simplify \\ \\ second \ equation \\ \\ -2x + 4 \ \textgreater \ 8 \ / \ simplify \\ \\ -2x \ \textgreater \ 8 - 4 \ / \ subtract \ 4 \ from \ each \ side \\ \\ -2x \ \textgreater \ 4 \ / \ simplify \\ \\ x \ \textless \ \frac{4}{-2} \ / \ divide \ each \ side \ by \ -2 \\ \\$
$\\ \\ x \ \textless \ - \frac{4}{2} \ / \ simplify \\ \\ x \ \textless \ - 2 \ / \ simplify \\ \\ collect \ solutions \\ \\ x \ \textgreater \ 6 \ , \ x \ \textless \ -2 \\ \\$

So, your answer to this problem is x > 6 and x < -2.

8 0

3 years ago

One company estimates same-day delivery as more than three less than half the total number of miles. Which

-BARSIC- [3]

Answer:

Step-by-step explanation:

I took the quiz and got it right.

Also, the equation is y > x/2 - 3

8 0

3 years ago

Read 2 more answers

377. Dawn wants to compare the volume of a basketball with the

olchik [2.2K]

Answer:

$V = \frac{4}{3} \pi R^{3}$ and

$v = \frac{4}{3} \pi r^{3}$

Step-by-step explanation:

Dawn wants to compare the volume of a basketball with the volume of a tennis ball.

Now, if the radius of the basketball is R and that of the tennis ball is r, then the formula that can be used to determine the volume of each ball will be

$V = \frac{4}{3} \pi R^{3}$ and

$v = \frac{4}{3} \pi r^{3}$

Now, dividing V by v we can compare the volume of the basketball and the tennis ball. (Answer)

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3 years ago

Three ice cream cones cost 8.25,at this rate how much does 2 ice creams cones cost for two cones

Sav [38]

Answer:

5.50

Step-by-step explanation:

If three cones cost 8.25, then each cone should cost 2.75. (8.25 / 3 = 2.75)

Then 2 cones should cost 5.50 (2.75 x 2 = 5.50)

5 0

3 years ago

Prove that (81/16)^-3/4 ×[(25/9)^-3/2 ÷ (5/2)^-3]=1

andreev551 [17]

Answer:

First write them in positive exponent form

(16/81)¾ × [ (9/25)^3/2 ÷ (2/5)³ ]

(2⁴×¾)/ (3⁴×¾) × [ (3² × ^3/2) / (5² ×^3/2) ÷ 2³/5³)

Simplify the terms

2³/3³ × ( 3³ / 5³ ÷ 2³/5³)

Solve the terms in the bracket

2³/3³ × (3³/5³×5³/2³)

You will get

2³/3³ × 3³/2³ = 1

They will cancel each other so the answer will be 1

Hope this helps.

8 0

3 years ago