Reactant C is the limiting reactant in this scenario.
Explanation:
The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.
Balanced chemical reaction is:
A + 2B + 3C → 2D + E
number of moles
A = 0.50 mole
B = 0.60 moles
C = 0.90 moles
Taking A as the reactant
1 mole of A reacted to form 2 moles of D
0.50 moles of A will produce 
= 
thus 0.50 moles of A will produce 1 mole of D
Taking B as the reactant
2 moles of B reacted to form 2 moles of D
0.60 moles of B reacted to form x moles of D
= 
x = 2 moles of D is produced.
Taking C as the reactant:
3 moles of C reacted to form 2 moles of D
O.9 moles of C reacted to form x moles of D
= 
= 0.60 moles of D is formed.
Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.
Answer:
C. Solid
Explanation:
It's most about the kinetic energy, when molecules have the least amount of room to move around, they have the least amount of energy.
For example if you think about gas and how spread out the molecules are in order to evaporate, there it the highest amount of energy there.
4.1g
Explanation:
Given parameters:
Mass of carbon dioxide = 15g
Mass of oxygen gas = 11g
Unknown:
Mass of carbon consumed = ?
Solution:
Equation of the reaction:
C + O₂ → CO₂
To solve this problem from the balanced equation, we have to use the amount of product formed and work to Carbon. This is because, we are sure of the amount of carbon dioxide formed but the amount of the given oxygen gas used is not precise.
Number of moles of CO₂ = 
Molar mass of CO₂ = 12 + (16 x2) = 44g/mol
Number of moles of CO₂ = 
= 0.34mole
From the equation of the reaction;
1 mole of CO₂ is produced from 1 mole of C
0.34mole of CO₂ will produce 0.34mole of C
Mass of carbon reacting = number of moles x molar mass = 0.34 x 12 = 4.1g
Learn more:
Number of moles brainly.com/question/1841136
#learnwithBrainly
Answer:
6.75 moles of CuCl₂ were used
Explanation:
Given data:
Number of moles of AlCl₃ formed = 4.5 mol
Number of moles of CuCl₂ used = ?
Solution:
Chemical equation:
3CuCl₂ + 2Al → 2AlCl₃ + 3Cu
Now we will compare the moles of CuCl₂ and AlCl₃
AlCl₃ : CuCl₂
2 : 3
4.5 : 3/2×4.5 = 6.75
6.75 moles of CuCl₂ were used.
