Answer:
Option D. 0.115 M
Explanation:
The following data were obtained from the question:
Mass of CuSO4 = 36.8 g
Volume of solution = 2 L
Molar mass of CuSO4 = 159.62 g/mol
Molarity of CuSO4 =..?
Next, we shall determine the number of mole in 36.8 g of CuSO4.
This can be obtained as shown below:
Mass of CuSO4 = 36.8 g
Molar mass of CuSO4 = 159.62 g/mol
Mole of CuSO4 =.?
Mole = mass /Molar mass
Mole of CuSO4 = 36.8 / 159.62
Mole of CuSO4 = 0.23 mole
Finally, we shall determine the molarity of the CuSO4 solution as illustrated below:
Mole of CuSO4 = 0.23 mole
Volume of solution = 2 L
Molarity of CuSO4 =..?
Molarity = mole /Volume
Molarity of CuSO4 = 0.23 / 2
Molarity of CuSO4 = 0.115 M
Therefore, the molarity of the CuSO4 solution is 0.115 M.
Answer: Event 1 is an example of a physical change and Event 2 is an example of a chemical change.
Explanation: Physical change is one in which there is no change in chemical composition of the substance. There is only a change in phase change.
Chemical change is a change in which there is a change in chemical composition and there might or might not be a phase change.
On Boiling, the water molecules remain bonded in the same form and only covert from liquid to gaseous form, thus is a physical change.
On Rusting of iron nail, the iron changes to iron oxide by combining with oxygen, there is a rearrangement of atoms and thus is a chemical change.
Answer:
The answer is letter A. Diamond
Explanation:
The diamond is a crystalline form of carbon, with a cubic structure, of the sp³ type, that is, each carbon atom of the structure is linked to four other carbon atoms, forming a tetrahedral geometry.
Answer:
See explanation
Explanation:
On the pH scale acidity ranges from pH values of 0-6.9. Natural rain water is slightly acidic due to the presence of carbon dioxide in the atmosphere which is an anhydride of carbonic acid.
CO2(g) + H2O(l) -------> H2CO3(aq)
B. The equations that turn sulfur to sulfuric acid are;
S(l) + O2(g) -----> SO2(g)
2SO2(l) + O2(g) -----> 2SO3(g)
SO3(g) + H2SO4(l) -----> H2S2O7(l)
H2S2O7(l) + H2O(l) ----> 2H2SO4(l)
-
At pH 6, H^+ concentration = 1 * 10^-6 M
At pH 2, H^+ concentration = 1 * 10^-2 M
Hence;
1 * 10^-2/1 * 10^-6
= 10^4 times more acidic
