The net charge on the structure as shown in the question is -1.
<h3>What is a charged specie?</h3>
We say that a specie is charged if the specie has an excess of positive or negative charge. An excess of the positive charge means that the substance is positively charged while an excess if the negative charge simply means that the object is negative charged.
When we have a chemical structure as we have seen, it is possible that the structure as we have it could have a net charge. The net charge that the structure has can be deduced by looking at the formal charges that are carried by all the atoms that we have in the system.
The charge as we can see that is on the central atom of the molecule is the -1 charge hence this is the charge that is carried overall by the molecule.
If we then look at the structure as we can see, we can see that there is a charge of negative one that is attached to the atom of chlorine as is clearly visible and obvious from the image attached to the question.
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<span>This question asksyou to apply Hess's law.
You have to look for how to add up all the reaction so that you get the net equation as the combustion for benzene. The net reaction should look something like C6H6(l)+ O2 (g)-->CO2(g) +H2O(l). So, you need to add up the reaction in a way so that you can cancel H2 and C.
multiply 2 H2(g) + O2 (g) --> 2H2O(l) delta H= -572 kJ by 3
multiply C(s) + O2(g) --> CO2(g) delta H= -394 kJ by 12
multiply 6C(s) + 3 H2(g) --> C6H6(l) delta H= +49 kJ by 2 after reversing the equation.
Then,
6 H2(g) + 3O2 (g) --> 6H2O(l) delta H= -1716 kJ
12C(s) + 12O2(g) --> 12CO2(g) delta H= -4728 kJ
2C6H6(l) --> 12 C(s) + 6 H2(g) delta H= - 98 kJ
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2C6H6(l) + 16O2 (g)-->12CO2(g) + 6H2O(l) delta H= - 6542 kJ
I hope this helps and my answer is right.</span>
Density<span> is </span>defined<span> as the ratio between mass and volume or mass per unit volume.
Source is google
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Answer:2800 degrees
Explanation:when iron soild becomes a liquid at 2800 degrees Fahrenheit
Answer:
Explanation:
Hello there!
In this case, since we need to dilute the 1.75-M HCl, and the total number of moles remain unchanged, we can write:
And in terms of volume and concentration:
Thus, we can solve for the volume of the concentrated HCl as shown below:
Therefore, we plug in the data to get:
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