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3 years ago

How many protons does the largest transition metal have in its nucleus?

Chemistry

2 answers:

lara [203]3 years ago

6 0

The largest transition metal is 112 protons

CaHeK987 [17]3 years ago

4 0

The largest transition metal is copernicium with 112 protons

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calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.

Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

$P_w=P_p+P_s$

$P_w=P_p+(-iCRT)$

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= $P_w$

$P_p=0 bar$ (At standard temperature)

$P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar$

$P_w=0 bar+(-3.406 ) bar$

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0

3 years ago

What are the names of the components (each shown with a leader and a line) of a circuit shown in the diagram?

kakasveta [241]

It could be source for the battery, switch or interrupter for the lever, charge for the bulb and conductor for the wire.

7 0

4 years ago

The part that includes land and water

luda_lava [24]

Answer: this is all of it

Explanation: i know this because its all of it

6 0

3 years ago

Read 2 more answers

Someone who is good at chemistry please help me

erastovalidia [21]

Equation#1 - Ca(s)+Cl2(g) ——> CaCl2(s)
Word equation #1- Calcium and Chlorine react to form Calcium Chloride.

Equation #2- N + I3 —-> I3N
Word Equation #2- Nitrogen and Iodine react to form nitrogen triiodine.

6 0

3 years ago

Acenapthalene has the empirical formula C6H5. A solution of 0.515 g of acenapthalene in 15.0 g CHCl3 boils at 62.5oC. The normal

german

Answer:

The molecular formula of an ascenapthalene is $C_{12}H_{10}$

Explanation:

$\Delta T_b=K_b\times m$

$\Delta T_b=K_b\times \frac{\text{Mass of acenapthalene}}{\text{Molar mass of acenapthalene}\times \text{Mass of chloroform in Kg}}$

where,

$\Delta T_f$ =Elevation in boiling point = $(62.5-61.7)^oC=0.8^oC$

Mass of acenapthalene = 0.515 g

Mass of $CHCl_3$ = 15.0 g = 0.015 kg (1 kg = 1000 g)

$K_b$ = boiling point constant = 3.63 °C/m

m = molality

Now put all the given values in this formula, we get

$0.8^0C=3.67 ^oC/m\times \frac{0.515}{\text{Molar mass of acenapthalene}\times 0.015kg}$

$\text{Molar mass of acenapthalene}=155.7875 g/mol$

Let the molecule formula of the Acenapthalene be $C_{6n]H_{5n}$

$6n\times 12 g/mol+5n\times 1 g/mol=155.7875 g/mol$

n = 2.0

The molecular formula of an ascenapthalene is $C_{12}H_{10}$

4 0

4 years ago