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ale4655 [162]
3 years ago
15

Stephen averaged 32.3 points a game. LeBron averaged 29.4 points a game. What was the difference between their averages?

Mathematics
1 answer:
Lynna [10]3 years ago
3 0
Stephen avenged 2.9 points more then lebron
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Suppose it is known that for a given differentiable function y=f(x), its tangent line (local linearization) at the point where a
AleksandrR [38]

Answer:

y(-4) = 5

y'(-4) = -7

Step-by-step explanation:

Hi!

Since the tangent line T and the curve y must coincide at x=-4

y(-4) = T(-4) = 5

On the other hand, the derivative of the curve evaluated at -4 y'(x=-4) must be the slope of the tangent line. Which inspecting the tangent line T(x) is -7

That is:

y'(-4) = -7

6 0
2 years ago
Help ASAP I need help with this
Ulleksa [173]

Draw 27 circles and take off 4.5 circles for every hour. The answer will be 6 hrs.

Expression:

-27/-4.5 I believe

7 0
3 years ago
What is the following equation written in standard form?<br> –3x² + 7x=9<br> NEED HELP ASAP
yKpoI14uk [10]

Answer:

-3x^2 + 7x - 9 = 0

The third answer

3 0
2 years ago
6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the
MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

a_1 the horizontal distance between the first observer and the ballonist

a_2 the horizontal distance between the second observer and the ballonist

\alpha _1 and \alpha _2 the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

And for S_2 will be the same:

S_2=\frac{h^{2} }{\tan(\alpha _2)}

Replacing in the equation 2:

S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

So, we can replace all the known data in the last equation:

h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0
2 years ago
consider the four corners of the front wall of a rectangular class room (upper right, upper left, lower left, upper left) which
professor190 [17]
(You copied 'upper left' twice, and you left out 'lower right'. 
But we know what you mean.)

If those are the corners of the wall, then they're ALL in the plane of
the wall (coplanar with it).
3 0
3 years ago
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