Question

If both zeroes of quadratic polynomial (k+2)x^2-(k-2)x-5 are equal in magnitude but opposite in sign find k

Answer 1

Answer:

k=2

Step-by-step explanation:

$(k + 2) {}^{2} - (k - 2)x - 5 = 0$

If we have two zeroes that are equal in size, but different signs then we have a different of squares,

$(a + b)(a - b) = {a}^{2} - b {}^{2}$

So in order to do this we must make the middle term, x 0 so

$k - 2 = 0$

$k = 2$