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GarryVolchara [31]
2 years ago
12

the average car on the highway travels 65 miles per hour. if someone has been driving for 4.5 hours how many miles have they dri

ven (Help)
Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
3 0

Answer:

292.5

Step-by-step explanation:

Since they are driving 65 miles for every hour, you can multiply the 65 miles by 4.5

So:

65 * 4.5 = 292.5

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Least common multiple of 168 and 76
yuradex [85]

Answer:

Best to draw out a factor tree.

4 0
2 years ago
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Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0
3 years ago
Which scatter plot represents the data in the table?
TEA [102]
In order to answer this question, you need to know what should be in the x axis and what should be in the y axis.

As for this one, you have given the information of the table:<span>
Park patrons Number of dogs
7 4
6 2
9 7
8 6
5 3
7 7
3 1
4 3

The value in the x axis should be the </span>Park patrons
The value in the y axis should be the Number of dogs
4 0
3 years ago
15/3+30/3= how I can solve it ?
Kazeer [188]
15/3=5
30/3=10

5+10=15
3 0
3 years ago
13. Marco's height is 63 inches. Marco's height is 3 inches less than 1.5 times Jennifer's height.
qaws [65]

Answer:

Jennifer is 90 inches tall

Step-by-step explanation:

5 0
3 years ago
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