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Fiesta28 [93]
3 years ago
11

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP *67 points*

Mathematics
1 answer:
ycow [4]3 years ago
4 0

If it didn't have that piece cut out on the bottom, it would be a rectangle that's 9cm wide and 5cm high.  Its area would be 9x5= 45 cm².

But that piece is cut out of the bottom.  The cut-out piece is 3cm wide and 3cm high, so its area is 3x3= 9 cm².

9 cm²  have been cut out of the 45 cm²  of the complete big rectangle.  So the remaining area of the figure is  45 - 9 =<em> 36 cm²</em> .

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A cable is <br> 40<br><br> meters long. How long is the cable in decimeters?
AnnyKZ [126]
Hello,

1 meter is equal to 10 decimeters.

SO, 
if we convert 40 meters to decimeters, we multiply 40 meters by 10 decimeters, getting 400 decimeters.

Hope this helps!

May
6 0
4 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
Please help! Don't answer if your not sure.
gavmur [86]

Answerthats good

Step-by-step explanation:

i will answer

5 0
3 years ago
A gumball machine has 220 red gumballs. If the red gumballs are 50% of the total number of gumballs, how many gumballs are in
JulijaS [17]
Answer:

440

Explanation:

If 50% of the total gum balls are red which is 220, then the other 50% is 220.
5 0
3 years ago
Read 2 more answers
HURRY PLEASEEE PLEASE PLEASE!!!!!!!!!
Likurg_2 [28]

Answer: 2000 tickets were sold

Step-by-step explanation:

8000 divided by 40 percent is 200

6 0
3 years ago
Read 2 more answers
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