The answer is -3, i had a test with the same question
Answer:
And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution 
and for this case we know that the distribution is given by:
And the standard error would be:
And replacing we got:
Step-by-step explanation:
For this case we know the population deviation given by:
And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution and for this case we know that the distribution is given by:
And the standard error would be:
And replacing we got:
Answer:
T (5, 5)
Step-by-step explanation:
T(P)= (x+1, y+3) = (4+1, 2+3)
Answer:
domain: {x | x is a real number}
range: {y l y> -8}
Step-by-step explanation:
f(x) = 4x² – 8 is a parabola, a U shape.
Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.
y > -8 because the minimum is -8.
Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.
Quadratic standard form:
f(x) = ax² + bx + c
"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.
"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.
"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.
Answer:
4/-2
Step-by-step explanation:
Start at a point where the line intersects a firm coordinate like y=2 then use rise/run rise is vertical and run is horizontal count from the intersection up to where the line intersects another firm point in this case y=6 then count the run which lands on x=-2 y=6 which gives you the slope of 4/-2
