The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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Answer:
7x21
Step-by-step explanation:
First, we need to find the length of the pool. Since it is three times as long as it is wide, it is 21 feet long (7 x 3 = 21). That way we can tell that it is 7x21, with a perimeter of 56 feet, and an area of 147 feet squared.
The average speed would be 53 miles per hour, hope this helped, if you need me to explain then here is the way, so all you do is divide 265 by 5 and what I did to help make it faster was split 265 into 250 and 15 so 250 divided by 5 is 50 and 15 divided by 5 is 3 so 50 + 3 = 53!
We have the following function:
f(t) = −16t2 + 34t + 546
By definition, the average rate of change is:
Avr = (f (t2) - f (t1)) / (t2 - t1)
We have then:
For t1 = 5:
f (5) = -16*(5)^2 + 34*(5) + 546
f (5) = 316
For t2 = 5:
f (7) = -16*(7)^2 + 34*(7) + 546
f (7) = 0
Substituting values:
Avr = (0 - 316) / (7 - 5)
Avr = -158
Answer:
The average rate of change of f (t) from t = 5 seconds to t = 7 seconds is -158 feet per second.
