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Nastasia [14]
3 years ago
14

Solve the equation. 19 = 14 + k k=

Mathematics
2 answers:
Fed [463]3 years ago
7 0

Answer:

5

Step-by-step explanation:

19-14=5

Iteru [2.4K]3 years ago
4 0
Solve for k by simplifying both sides of the equation, then isolating the variable .

Answer - K=5

Hope this helps!
Have a great day! :)
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Solve for x: |2x + 6| − 4 = 20
lord [1]
I believe the answer is C
5 0
3 years ago
The width of a rectangle is 2x + 4 and the length of the
iren [92.7K]

Given:

Width of a rectangle = 2x+4

Length of the rectangle = 6x+12

To find:

The ratio of the width to the length.

Solution:

We need to find the ratio of the width to the length.

\text{Required Ratio}=\dfrac{\text{Width}}{\text{Length}}

Putting the given values, we get

\text{Required Ratio}=\dfrac{2x+4}{6x+12}

\text{Required Ratio}=\dfrac{2(x+2)}{6(x+2)}

\text{Required Ratio}=\dfrac{2}{6}

\text{Required Ratio}=\dfrac{1}{3}

\text{Required Ratio}=1:3

Therefore, the ratio of the width to the length is 1:3.

8 0
3 years ago
Solve each proportion. 9/8 = x/7
Alona [7]

Answer:

x=63/8

Step-by-step explanation:

9/8=x/7

or, 9*7=x*8

or, 63=8x

x=63/8

3 0
2 years ago
L.B. Johnson Middle School held a track and field event during the school year. The chess club sold various drink and snack item
elena55 [62]

Answer: $5.5

Step-by-step explanation:

Here is the complete question:

L.B. Johnson Middle School held a track and field event during the school year. The chess club sold various drink and snack items for the participants and the audience. Altogether, they sold 486 items that totaled $2,673 a. If the chess club sold each item for the same price, calculate the price of each item. b. Explain the value of each digit in your answer to a using place value terms

Item sold = 486

Total amount = $2673

Price of each item = Total amount/items sold

= 2673/486

= $5.5

Each item costs $5.5.

5.5 = 5 units and 5 tenths.

The first number after the decimal point by the right is the tenths.

8 0
4 years ago
What is the answered<br><br><br>pp lssss answer
pochemuha

\boxed{ \underline{ \bf \: Categorical}} \sf \: data \: set \: is \: the \: data \: set \\ \sf \: that \:  deals \: with \: only \: non \: numerical \: values.

6 0
3 years ago
Read 2 more answers
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