First of all, we can observe that

So the expression becomes

This means that the expression is defined for every 
Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

Since we can't accept 3 as an answer, the actual solution set is
![(-\infty,-2] \cup [2,3) \cup (3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%20%5Ccup%20%5B2%2C3%29%20%5Ccup%20%283%2C%5Cinfty%29)
Answer:
exponent i think.
Step-by-step explanation:
Answer: The snack shop sells granola bars for a lower price.
Step-by-step explanation:
First you should plug in the number of bars for each equation, if you get one bar from the snack shop the price would be $1.25, I'm going to fill in the table to help you better understand.
y= 1.25(2) 2.50
y= 1.25(3) 3.75
y= 1.25(4) 5.00
y= 1.25(5) 6.25
This table was all for the snack shop.
Answer:

Step-by-step explanation:
Given expression,

=>
We see that
is common in both numerator and denominator
hence canceling out we get:-

Answer=