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valkas [14]
3 years ago
12

One researcher wishes to estimate the mean number of hours that high school students spend watching tv on a weekday. a margin of

error of 0.23 hour is desired. past studies suggest that a population standard deviation of 1.9 hours is reasonable. estimate the minimum sample size required to estimate the population mean with the stated accuracy.
Mathematics
2 answers:
PtichkaEL [24]3 years ago
3 0
Margin of error, e = Z*SD/Sqrt (N), where N = Sample population

Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96

Therefore,
0.23 = 1.96*1.9/Sqrt (N)

Sqrt (N) = 1.96*1.9/0.23

N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263

Minimum sample size required is 263 students.

yawa3891 [41]3 years ago
3 0

Answer:the answer is 236 students


Step-by-step explanation:


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Given the box plot, will the mean or the median provide a better description of the center? box plot with min at 11, Q1 at 22. 5
Slav-nsk [51]

The median, because the data distribution is skewed to the right.

Given that

The box plot with the following parameters:  

Minimum value at 11,

First Quartile, Q1 at 22.5,

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Third Quartile, Q3 at 36,

Maximum value at 37.5.

According to the question

When a distribution has a longer tail to one of its sides, then it is said to be skewed.

Since the tail is longer to the left, it is said to be left-skewed.

The data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile  (22.5).

For skewed data, we always prefer the median because it is less affected by the outliers and if the mean is chosen, the value of the mean is biased towards the side that has larger values while the median does not get affected by it. So, we choose the median.

For skewed distributions, the median is the best measure of center.

Hence, the median, because the data distribution is skewed to the right.

To know more about Mean click the link given below.

brainly.com/question/2508120

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