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Vladimir [108]
3 years ago
5

From the coordinate 8,12 to 10 and 15 what was the scale factor

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Answer:

Scale factor is 5/4

Step-by-step explanation:

To find scale factor make a fraction. New coordinates/old coordinates

Make the fractions and reduce.

10/8  and 15/12

5/4 and 5/4

The scale factor is 5/4

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Indicate in standard form the equation of the line passing through the given points.
lorasvet [3.4K]

Answer:

y = 6

Step-by-step explanation:

Let the y-intercept form of the equation of the line is,

y = mx + b

Here, m = Slope of the line

b = y-intercept

Slope of the line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

m = \frac{y_2-y_1}{x_2-x_1}

Slope of the passing through (0, 6) and (5, 6) will be,

m = \frac{6-6}{0-5}

m = 0

Equation of the line with m = 0 will be,

y = 0 + b

y = b

Since, line passes through (0, 6),

By substituting the values in the equation,

b = 6

Therefore, standard equation of the line passing through (0, 6) and (5, 6) will be,

y = 6

6 0
3 years ago
On a quiz there are four-mulptiple choice questions worth 3 points each and two true/false questions worth 1 point​
Scilla [17]

Answer:

15

Step-by-step explanation:

7 0
3 years ago
a carpet cost $15 per square foot. ( When calculating the price, any fraction of a square foot is counting as a whole square foo
gregori [183]
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5 0
4 years ago
What are the domain values for the function f(x) = 2x + 3 if the range values are (-1, 1, 2,4}
ArbitrLikvidat [17]

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

So i think it will be -1

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John read the first 114 pages of a novel, which was 3 pages less than 1/3 of the novel.
Naya [18.7K]

Answer:

[351]

Step-by-step explanation:

114 + 3 = 117. 117 x 3 = 351.

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3 years ago
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