Answer:
\frac{17}{24}
Step-by-step explanation:
Given that Box 1 contains 2 red balls and 1 blue ball. Box 2 contains 3 blue balls and 1 red ball. A coin is tossed. If it falls heads up, box 1 is selected and a ball is drawn. If it falls tails up, box 2 is selected and a ball is drawn.
P(selecting Box 1) = 0.5 = P(selecting II box) (assuming a fair coin is tossed)
P(Red/Box I ) = ![\frac{2}{2+1} =\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B2%2B1%7D%20%3D%5Cfrac%7B2%7D%7B3%7D)
P(Red/Box II) = ![\frac{3}{3+1} =\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B3%2B1%7D%20%3D%5Cfrac%7B3%7D%7B4%7D)
Box 1 and Box 2 are mutually exclusive and exhaustive events.
So probability of selecting a red ball.
= probability of selecting a red ball from box 1 + probability of selecting a red ball frm box 2
![=P(B1)*P(Red/B1) + P(B2)*P(Red/B2)\\= \frac{1}{2} * \frac{2}{3} + \frac{1}{2} * \frac{3}{4} \\= \frac{1}{3} + \frac{3}{8} \\= \frac{17}{24}](https://tex.z-dn.net/?f=%3DP%28B1%29%2AP%28Red%2FB1%29%20%2B%20P%28B2%29%2AP%28Red%2FB2%29%5C%5C%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%5Cfrac%7B2%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20%5Cfrac%7B3%7D%7B4%7D%20%5C%5C%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2B%20%5Cfrac%7B3%7D%7B8%7D%20%5C%5C%3D%20%5Cfrac%7B17%7D%7B24%7D)
Make the lesser number x and the other y
x=y-.25y
.75y=x
Now make y anything you want
Say 100.
y=100, x=.75 x 100=75
75 and 100
Hope this helps :)
Answer:
Step-by-step explanation:
60+(4.735-0.92)
60+3.81500
63.81500
Answer:
x=40
Step-by-step explanation:
3x+60=180 1. -60 on both sides
3x = 120 2./3 on both sides
x=40